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zhannawk [14.2K]
3 years ago
6

Evaluate the expression. If necessary, round to the nearest hundredth. lne^3x^2

Mathematics
2 answers:
tester [92]3 years ago
7 0
<span>lne^3x^2

by the properties of logarithm

lna^x  = xlna

so, the equation goes by

3x^2 lne; lne = 1

so the equation is 3x^2</span>
Naya [18.7K]3 years ago
5 0
For this case we have the following expression:
 lne ^ 3x ^ 2
 Rewriting we have:
 ln (e ^ (3x ^ 2))
 By properties of the natural and exponential logarithm function, we can
rewrite the expression as:
 ln (e ^ (3x ^ 2)) = 3x ^ 2
 Answer:
 
The equivalent expression is given by:
 
3x ^ 2
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Answer:

a) 28

b)

Class Limits  Class Boundaries   Midpoint    f      Rf         Cf

10 - 37            9.5-37.5                   23.5            7     0.096     7      

38 - 65           37.5-65.5                 51.5           25    0.342     32    

66 - 93           65.5-93.5                 79.5          26    0.356     58    

94 -  121        93.5-121.5                   107.5         9     0.123       67    

122 - 149      121.5-149.5                  135.5         5      0.068     72  

150 - 177       149.5-177.5                  163.5        0         0.0      72    

178 - 205       177.5-20.5                  191.5         1       0.014      73  

Total                                                                  73          1.0    

c)

The histogram is in attached file.

Step-by-step explanation:

a)

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx
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