Answer:
uh because life sucks o_<
Answer:
the state of the circuit is a function of the voltage level. The interpretation is up to the user.
Explanation:
A binary digital circuit adopts one of two states, depending on whether the voltage level is above or below some threshold that depends on the design of the circuit. Within each state, the voltage may have some typical range. When the voltage is near the threshold, the state of the circuit may actually be "indeterminate".
The internal/output voltage is a function of the state of the circuit. The interpretation of that voltage as a true/false or 1/0 or other meaning is up to the user of the circuit.
The circuit interprets a given input voltage as intending to convey a particular input signal state according to the circuit specifications. Input voltages near the threshold between states may cause unexpected or even destructive results.
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In order to conserve space, some digital circuits use more than 2 different voltage levels to signify more than 2 different states.
Answer / Explanation:
To proper understand the answers that is given to the question, we need to understand some basic terms that has been used in the question.
Energy: This can be refereed to as the quantitative property that is transferred to an object for the purpose of the object working or to heat up the object. It can also be referred to as conserved quantity that is energy can be converted from one form or state to another but cannot destroyed.
Power: This can be defined as the rate of doing work or transferring heat per unit time from one state to another. The SI Units of power is watt which is equal to one joule per second.
Hence, the formula that links energy and power is:
Energy = Power x Time
Now. referring back to the question (a) asking how much energy do we save if we execute at the current speed and turn off the system when the computation is complete: The answer is = 50%. That is 50% of the energy is saved.
(b) If we recall the formula for calculating energy,
we have:
Energy = 1 /2 Load x V²
Changing the frequency does not affect the energy.However, it affects the power.
So therefore, the new energy is 1 / 2 Load x ( 1/2 V)² ,
reducing it to about 1 /4 of the old energy.
