Answer:
Option B
1025 psi
Explanation:
In a single shear, the shear area is
The shear strength=
and in this case
Shear strength=
hence making load the subject then
Load=Shear area X Shear strength
Load=
Answer:
volumetric flow rate = 
Velocity in pipe section 1 = 
velocity in pipe section 2 = 12.79 m/s
Explanation:
We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.
The density of water is = 997 kg/m³
density = mass/ volume
since we are given the mass, therefore, the volume will be mass/density
25/997 = 
volumetric flow rate = 
Average velocity calculations:
<em>Pipe section A:</em>
cross-sectional area =

mass flow rate = density X cross-sectional area X velocity
velocity = mass flow rate /(density X cross-sectional area)

<em>Pipe section B:</em>
cross-sectional area =

mass flow rate = density X cross-sectional area X velocity
velocity = mass flow rate /(density X cross-sectional area)

The expression of V(m³)=e^(t(s)) to make V in in³ and t in minutes is;
V(in³) = (¹/₆₁₀₂₄)a
We are given that;
Volume of microbial culture is observed to increase according to the formula;
V = e^(t)
where;
t is in seconds
V is in m³
We want to now express V in in³ and t in minutes.
Now, from conversions;
1 m³ = 61024 in³
Also; 1 second = 1/60 minutes
according to formula for exponential decay, we know that;
V = ae^(bt)
Thus, we have;
61024V = ae^(¹/₆₀b(t(h))
V(in³) = (¹/₆₁₀₂₄)a
Read more about subject of formula at; brainly.com/question/790938
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