Question

A double-replacement reaction takes place when aqueous Na,co, reacts with aqueous Sn(NO3), according to the following equation. Na,co, + Sn(NO,)
You would expect one of the products of this reaction to be
20
Sn2(CO3)2
NaNO,
O Nas
OCNO,

Answer 1

Answer:

$Sn(CO_3)_2$ and $NaNO_3$.

Explanation:

Hello there!

In this case, according to the described chemical reaction between sodium carbonate and tin nitrate, we can write the undergoing chemical reaction:

$2Na_2CO_3+Sn(NO_3)_4\rightarrow Sn(CO_3)_2+4NaNO_3$

Thus, we notice that the products are strontium carbonate and sodium nitrate, whose formulas are $Sn(CO_3)_2$ and $NaNO_3$ respectively.

Best regards!