Answer:
They don't have equal velocities
Explanation:
We have one bus travelling from Chicago to New York at 30 m/s and one bus travelling from Chicago to San Francisco at 30 m/s.
This is a cheat question. You need to remember that velocity is a vector. Remember that a vector has a direction and a module. So, the answer will be true, if both buses meet both conditions (direction and module). Let's start to analyze:
Module: In this case is 30 m/s for both buses
Direction: In this case is where the buses are heading. One is going to New York, and one is going to San Francisco. So the directions are different.
As module and direction are not the same for both buses we can say that they don't have equal velocities.
From the freezing temperature up to about 4°C (39°F) the water CONTRACTS. That is, it becomes MORE dense. I think I read that water is the ONLY known substance whose solid phase floats in its liquid phase. That's why the cubes float in your soda and bergs float in the ocean. And if weren't so, then life on Earth would not be possible ! Oceans and lakes would freeze from the bottom up, ONE TIME, and then never thaw again.
Characteristics help us to classify seeds because different plants have different features.
<h3>How are characteristics used to identify and classify plants?</h3>
The divisions classify plants that are based on whether they reproduce by spores or seeds. Spore-bearing plants include ferns, club mosses, and horsetail while on the other hand, Seed-bearing plants are divided into gymnosperms and angiosperms. Different plants have different characteristics and features so on the basis of these characteristics we can easily classify seeds whether they belong from angiosperm and gymnosperm.
So we can conclude that characteristics help us to classify seeds because different plants have different features.
Learn more about seeds here: brainly.com/question/18799172
#SPJ1
Answer:
s = 20 m
Explanation:
given,
mass of the roller blader = 60 Kg
length = 10 m
inclines at = 30°
coefficient of friction = 0.25
using conservation of energy
u = 9.89 m/s
Using second law of motion
ma =μ mg
a = μ g
a = 0.25 x 9.8
a = 2.45 m/s²
Using third equation of motion ,
v² - u² = 2 a s
0² - 9.89² = 2 x 2.45 x s
s = 20 m
the distance moved before stopping is 20 m
