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Dafna1 [17]
3 years ago
9

A drag racer starts from rest and accelerates at 7.4 m/s2. How far will he travel in 2.0 seconds?

Physics
1 answer:
Leto [7]3 years ago
3 0

Using the kinematic equation below we can determine the distance traveled if t=2, a=7.4m/s^2.  First we must determine the final velocity:

v_{final}=v_{initial}+\frac{1}{2}at\\\\v_{final}=0+(7.4m/s^2)(2s)=34.8m/s

Now we will determine the distance traveled:

v_{final}^2=v_{initial}^2+2a \Delta x\\\\\Delta x = \frac{v_{final}^2}{2a} =\frac{(34.8)^2}{(2)(7.4)}=81.83 m

Therefore, the drag racer traveled 81.83 meters in 2 seconds.

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In your own words, explain the effects of time dilation.
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3 years ago
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What is the mass of 3.70 L of water? Remember 1000 L = 1 m^3 (Unit=Kg)
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Answer:

3.7kg

Explanation:

The following data were obtained from the question:

Volume = 3.7L

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Next, we shall convert 3.7L to m³.

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1000L = 1m³

Therefore, 3.7L = 3.7/1000 = 0.0037m³

Now, we can obtain the mass of the water as shown below:

Density of water = 1000kg/m³

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Cross multiply

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3 years ago
Why are the plates in a capacitor parallel to each other?
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4 years ago
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The general kinematic equations of motion for vertical displacement can also be simplified significantly. Write the simplified
Setler [38]

Answer:

Δy = v₀t + (1/2)gt²

where g = 9.81 m/s if the body is moving downwards and g = -9.81 m/s if the body is moving upwards

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Answer:

lowest level contains more energy

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