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natta225 [31]
3 years ago
15

A central air conditioner in a typical American home operates on a 220-V circuit and draws about 15 A

Physics
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

Find answers below.

Explanation:

Given the following data;

Voltage = 220V

Current = 15 A

a. To find the power;

Power = current * voltage

Power = 15 * 220

Power = 3300 Watts

b. To find the energy;

Time = 8 hours = 60 * 60 * 8 = 28800 seconds

Energy = power * time

Energy = 3300 * 8

Energy = 26400

Energy = 26.4 Kwh

c. Cost = 13 cents

Cost = 13 * 31 * 26.4

Cost = 106392 cents

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PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer these correctly!!!! (40pts)
Sunny_sXe [5.5K]

friction make non moving objects starts to move

  • true

there are different types of force which may help them to move

3 0
3 years ago
If I = 2.0 A in the circuit segment shown below, what is the potential difference VB - VA?
Tom [10]

Answer:

10 V

Explanation:

The potential difference between two points is the amount of work required to carry a unit charge from one point to the other point. This would result in a potential difference between this two points.

The difference between the potential across two points B and A is V_{BA}=V_B-V_A

From the image attached:

V_B-V_A=10-10I+20\\\\But\ I = 2A,hence:\\\\V_B-V_A=10-10(2)+20\\\\V_B-V_A=10-20+20\\\\V_B-V_A=10\ V

7 0
3 years ago
ILL MARK BRAINLIEST
77julia77 [94]

Answer: B

Longitudinal wave

Explanation:

Transverse waves have crests and troughs

Longitudinal waves have compressions and rarefactions. A compression is where the density of the wave medium is highest. While a rarefaction is where the density of the wave medium is lowest.

Since sound wave is a longitudinal wave. And longitudinal wave exists apart from sound, we can therefore conclude that it's a longitudinal wave in spring.

8 0
3 years ago
Which of these is a key feature of an experimental study?
Pavlova-9 [17]
The key feature in the experimental study is C. <span>The treatment in the experiment must be applied to each of the individuals in the experimental group. This is because it is made sure that the variables and conditions in different correspondents are applied so that actual results may be concluded.</span>
7 0
3 years ago
Read 2 more answers
A gas expands against a constant external pressure of 2.00 atm until its volume has increased from 6.00 to 10.00 L. During this
mars1129 [50]

Answer:

ΔU = - 310.6 J (negative sign indicates decrease in internal energy)

W = 810.6 J

Explanation:

a.

Using first law of thermodynamics:

Q = ΔU + W

where,

Q = Heat Absorbed = 500 J

ΔU = Change in Internal Energy of Gas = ?

W = Work Done = PΔV =

P = Pressure = 2 atm = 202650 Pa

ΔV = Change in Volume = 10 L - 6 L = 4 L = 0.004 m³

Therefore,

Q = ΔU + PΔV

500 J = ΔU + (202650 Pa)(0.004 m³)

ΔU = 500 J - 810.6 J

<u>ΔU = - 310.6 J (negative sign indicates decrease in internal energy)</u>

<u></u>

b.

The work done can be simply calculated as:

W = PΔV

W = (202650 Pa)(0.004 m³)

<u>W = 810.6 J</u>

7 0
3 years ago
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