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Stella [2.4K]
3 years ago
6

Distinguish between thermal energy, temperature, and heat. (BE SPECIFIC & use physics vocabulary)

Physics
1 answer:
xz_007 [3.2K]3 years ago
3 0

Thermal energy can be defined as specific thermodynamic quantities as a part of energy transfer such as heat, which is a form of thermal energy flowing from hotter to colder objects. Temperature is a physical property of an object which specify whether the subject is hot or cold.

<u>Explanation:</u>

Difference between thermal energy, temperature and heat

<u>Thermal Energy</u>

Thermal energy is the total kinetic energy of molecules bundled up in the object. This energy is the heat exerted by the object which forms its temperature.

<u>Temperature</u>

In technical terms, temperature is the average kinetic energies measurement of molecules and atoms, present in an object. Simply, we can say, temperature defines how hot or how cold is a substance. Temperature relies on the kinetic energy of particles.

<u>Heat</u>

Transfer of thermal energy from a hotter to colder objects. Heat is different from temperature. Temperature is the mark to define how hot a substance is whereas, heat is the flow of thermal energy.

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Which of these forms due to the force of compression?
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A 4.30 g bullet moving at 943 m/s strikes a 730 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
Ymorist [56]

Answer:

(a)2.7 m/s

(b) 5.52 m/s

Explanation:

The total of the system would be conserved as no external force is acting on it.

Initial momentum = final momentum

⇒(4.30 g × 943 m/s) + (730 g × 0) = (4.30 g × 484 m/s) + (730 g × v)

⇒ 730 ×v = (4054.9 - 2081.2) =1973.7

⇒v=2.7 m/s

Thus, the resulting speed of the block is 2.7 m/s.

(b) since, the momentum is conserved, the speed of the bullet-block center of mass would be constant.

V_{COM} = \frac{m_b}{m_b+m_{bl}}v_{bi}=\frac{4.30}{4.30+730}\times 943 m/s = 5.52 m/s

Thus, the speed of the bullet-block center of mass is 5.52 m/s.

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A 6.00-μf parallel-plate capacitor has charges of 40.0 μc on its plates. how much potential energy is stored in this capacitor?
dedylja [7]

Thew energy stored in a capacitor of capacitance C and voltage between the plates V is

E=\frac{1}{2} CV^2=\frac{1}{2C} Q^2.

Substituting numerical value

E=\frac{1}{2*6*10^{-6}} (40*10^{-6})^2\\ E=133.33\; \mu J

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