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ELEN [110]
3 years ago
10

A rolling ball with a mass of 1.01 kg crashes into a wall. The wall exerts a force of 2.40 Newtons and stops the ball. What was

the magnitude of the acceleration of the ball at the time of the crash?
Physics
1 answer:
klemol [59]3 years ago
3 0

Answer:

Acceleration, a = 2.38m/s²

Explanation:

Given the following data;

Mass = 1.01 kg

Force = 2.4N

To find the acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

F = ma

Where;

  • F represents force.
  • m represents the mass of an object.
  • a represents acceleration.

Making acceleration (a) the subject, we have;

Acceleration, a = \frac{F}{m}

Substituting into the equation, we have;

Acceleration, a = \frac{2.4}{1.01}

<em>Acceleration, a = 2.38m/s²</em>

<em>Therefore, the magnitude of the acceleration of the ball at the time of the crash is 2.38 meters per seconds square. </em>

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Explanation:

I did the math

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4 years ago
What is the momentum of a car with a mass of 1,300 kg traveling at a speed of 28 m/s?
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Answer:

<h3>The answer is 36,400 kgm/s</h3>

Explanation:

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From the question

mass = 1,300 kg

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Hope this helps you

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4 years ago
During a baseball game, a batter hits a high .
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A proton traveling with speed 2 × 105 m/s in the -y direction passes through a region in which there is a uniform magnetic field
stepladder [879]

Answer:

\vec{E} =  1.2\times 10^5(-i)

Explanation:

Given that

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The resultant force on the proton given as

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For uniform motion acceleration should be zero.

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0=\vec{E}+ (\vec{v}\times \vec{B})

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\vec{E} =- 2\times 10^5(-j) \times 0.6(-k)

\vec{E} =-1.2\times 10^5(i)

\vec{E} = 1.2\times 10^5(-i)

Electric filed should be apply in the negative x direction.

5 0
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