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ELEN [110]
2 years ago
10

A rolling ball with a mass of 1.01 kg crashes into a wall. The wall exerts a force of 2.40 Newtons and stops the ball. What was

the magnitude of the acceleration of the ball at the time of the crash?
Physics
1 answer:
klemol [59]2 years ago
3 0

Answer:

Acceleration, a = 2.38m/s²

Explanation:

Given the following data;

Mass = 1.01 kg

Force = 2.4N

To find the acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

F = ma

Where;

  • F represents force.
  • m represents the mass of an object.
  • a represents acceleration.

Making acceleration (a) the subject, we have;

Acceleration, a = \frac{F}{m}

Substituting into the equation, we have;

Acceleration, a = \frac{2.4}{1.01}

<em>Acceleration, a = 2.38m/s²</em>

<em>Therefore, the magnitude of the acceleration of the ball at the time of the crash is 2.38 meters per seconds square. </em>

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3 years ago
The wavelength of light is 5000 angstrom. Express it in nm and m.
Ierofanga [76]

Answer:

1 angstrom = 0.1nm

5000 angstrom = 5000/1 × 0.1nm

<h3>= 500nm</h3>

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<h3>= 5 × 10^-7 m</h3>

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800 joules of work were done with a force of 200 newtons. Over what
Svetach [21]

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3 years ago
Two airplanes leave an airport at the same time. The velocity of the first airplane is 730 m/h at a heading of 44.3 ◦ . The velo
Goshia [24]

Answer:

So airplane will be 1324.9453 m apart after 2.9 hour

Explanation:

So if we draw the vectors of a 2d graph we see that the difference in angles is  = 83 - 44.3 = 83-44.3=38.7^{\circ}

Distance traveled by first plane = 730×2.9 = 2117 m

And distance traveled by second plane = 590×2.9 = 1711 m

We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 38.7.

Using the law of cosine, d^2 representing the distance between the planes, we see that:

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d = 1324.9453 m

4 0
3 years ago
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