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natima [27]
3 years ago
5

Name the first 20 elements on the periodic table

Chemistry
2 answers:
Sergeu [11.5K]3 years ago
8 0

Answer:

1HydrogenH2HeliumHe3LithiumLi4BerylliumBe5BoronB6CarbonC7NitrogenN8OxygenO9FluorineF10NeonNe11SodiumNa12MagnesiumMg13AluminiumAl14SiliconSi15PhosphorusP16SulfurS17ChlorineCl18ArgonAr19PotassiumK20CalciumCa

Helga [31]3 years ago
6 0

Answer:

  1. HYDROGEN
  2. HELIUM
  3. LITHIUM
  4. BERYLLIUM
  5. BORON
  6. CARBON
  7. NITROGEN
  8. OXYGEN
  9. FLUORINE
  10. NEON
  11. SODIUM
  12. MAGNESIUM
  13. ALUMINUM
  14. SILICONE
  15. PHOSPHORUS
  16. SULFUR
  17. CHLORINE
  18. ARGON
  19. POTASSIUM
  20. CALCIUM

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3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh
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Answer:

n_{C_6H_{10}}=0.03molC_6H_{10}

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}

Even thought, the volume could be also computed by using its density:

V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}

Best regards.

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There are 1.48 × 10²⁵ molecules of zinc oxide in a 2 kg sample. Details about number of molecules can be found below.

<h3>How to calculate number of molecules?</h3>

The number of molecules of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

According to this question, there are 2000g of ZnO in a sample. Zinc oxide has a molar mass of 81.38 g/mol.

no of moles = 2000g ÷ 81.38g/mol

no of moles = 24.57mol

number of molecules = 24.57 × 6.02 × 10²³

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Therefore, there are 1.48 × 10²⁵ molecules of zinc oxide in a 2 kg sample.

Learn more about number of molecules at: brainly.com/question/11815186

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