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4 years ago

SI4F2 Lewis Structure

1 answer:

3 0

Answer: A Lewis structure is a structural representation of a molecule where dots are used to show electron positions around the atoms and lines or dot pairs represent covalent bonds between atoms.

Explanation: Lewis structures are also called Lewis dot diagrams, electron dot diagrams, Lewis dot formulas, or electron dot formulas. Technically, Lewis structures and electron dot structures are different because electron dot structures show all electrons as dots, while Lewis structures indicate shared pairs in a chemical bond by drawing a line.

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Which structure is located between the auricle and the eardrum? O stirrup O ear canal O auditory nerve Ocochlea

Damm [24]

Answer:

The structure that is located between the auricle and the eardrum is the ear canal.

Explanation:

The ear canal, or external ear canal, is a a tubular hole about 30 mm long that runs from the auricle to the eardrum, forming part of the external ear.

Its function is to conduct sound, in the form of vibrations, from the outside to the eardrum. It also has the function of producing a viscous secretion called cerumen, capable of trapping dust particles and small foreign bodies.

Other options are not correct because:

<em>Stirrup is located in the middle ear, along with the anvil and hammer. </em>
<em>Cochlea is in the inner ear and continues with the auditory nerve.</em>

3 0

3 years ago

Find the volume of a box with length 25 cm, height 25 cm and width 1.0 m. Volume

mariarad [96]

The volume of a box with length 25 cm, height 25 cm and width 1.0 m is 0.0625m³.

Volume of the box which is a cuboid can be calculated by multiplying the length, breadth and height of the given box.

Volume of the box is given by the product of the length of the box, Height of the box and Breadth or width of the box.

Since, the box is a cuboid, hence the formula is given by the products of length, breadth and height.

Given,

length of the box= 25cm = 0.25m

Height of the box =25cm = 0.25m

width of the box= 1m

Volume = length × width × height of box

Volume = 0.25 × 0.25 × 1

Volume = 0.0625m³

The volume of the box is 0.0625m³.

Learn more about Volume here, brainly.com/question/23118276

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4 0

2 years ago

Which two particles in an atom have the same mass ? protons and electrons or protons and neutrons

Sergio [31]

Protons and neutrons have about the same mass. Electrons are the smallest out of the three, in fact, protons weigh 1,836 times more than an electron.

4 0

3 years ago

Oxygen gas can be prepared by heating potassium chlorate according to the following equation:

Cerrena [4.2K]

Moles KClO₃ = 0.239

<h3>Further explanation</h3>

Given

Reaction

2KClO₃(s) ⇒2KCl(s) + 3O₂(g)

P water = 23.8 mmHg

P tot = 758 mmHg

V = 9.07 L

T = 25 + 273 = 298 K

Required

moles of KClO₃

Solution

P tot = P O₂ + P water

P O₂ = P tot - P water

P O₂ = 758 - 23.8

P O₂ = 734.2 mmHg = 0.966 atm

moles O₂ :

n = PV/RT

n = 0.966 x 9.07 / 0.082 x 298

n = 0.358

From equation, mol ratio KClO₃ : O₂ = 2 : 3, so mol KClO₃ :

= 2/3 x mol O₂

= 2/3 x 0.358

= 0.239

4 0

3 years ago

If 24.3 g of NO and 13.8 g of O₂ are used to form NO₂, how many moles of excess reactant will be left over?2 NO (g) + O₂ (g) → 2

zhuklara [117]

Explanation:

2 NO (g) + O₂ (g) ----> 2 NO₂ (g)

24.3 g of NO are reacting with 13.8 g of O₂. First we can convert the mass of theses samples into moles using their molar masses.

molar mass of O = 16.00 g/mol

molar mass of N = 14.01 g/mol

molar mass of NO = 16.00 g/mol + 14.01 g/mol

molar mass of NO = 30.01 g/mol

molar mass of O₂ = 2 * 16.00 g/mol

molar mass of O₂ = 32.00 g/mol

moles of NO = 24.3 g * 1 mol/(30.01 g)

moles of NO = 0.810 moles

moles of O₂ = 13.8 g * 1 mol/(32.00 g)

moles of O₂ = 0.431 moles

Now, to determine the limiting reactant or the excess reactant we can find the number of moles of O₂ that will react with 0.810 moles of NO and the number of moles of NO that will react with 0.431 moles of O₂.

According to the coefficients of the reaction 2 moles of NO will react with 1 mol of O₂. Let's use that relationship to find the limiting reagent.

2 moles of NO = 1 mol of O₂

moles of O₂ = 0.810 moles of NO * 1 mol of O₂/(2 moles of NO)

moles of O₂ = 0.405 moles

moles of NO = 0.431 moles of O₂ * 2 moles of NO/(1 mol of O₂)

moles of NO = 0.862 moles

We found that we need 0.405 moles of O₂ to completely react with 0.810 moles of NO. Or, we need 0.862 moles of NO to completely react with ours 0.431 moles of NO.

We can say that NO is limiting our reaction and O₂ is in excess.

Only 0.405 moles of O₂ will react with 0.810 moles of NO. But we had 0.431 moles of it. Let's find the excess.

Excess of O₂ = 0.431 moles - 0.405 moles

Excess of O₂ = 0.026 moles

Answer: 0.026 moles is the number of moles of oxygen that will be left over.

4 0

1 year ago