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castortr0y [4]
3 years ago
6

What would be the change in pressure in a sealed 10.0 l vessel due to the formation of n2 gas when the ammonium nitrite in 2.40

l of 0.900 m nh4no2 decomposes at 25.0°c?
Chemistry
2 answers:
Elan Coil [88]3 years ago
6 0

Answer : The pressure of the gas will be, 5.285 atm

Solution : Given,

Volume of N_2 gas = 10 L

Temperature of gas = 25^oC=273+25=298K   (0^oC=273K)

Volume of NH_4NO_2 = 2.40 L

Molarity of the ammonium nitrate solution = 0.9 M

First we have to calculate the moles of ammonium nitrate.

\text{ Moles of }NH_4NO_2=\text{ Molarity of }NH_4NO_2\times \text{ Volume of }NH_4NO_2

\text{ Moles of }NH_4NO_2=(0.9mole/L)\times (2.40L)=2.16moles

The balanced chemical reaction is,

NH_4NO_2\rightarrow N_2+2H_2O

From the balanced reaction, we conclude that

1 mole of NH_4NO_2 decomposes to give 1 mole of N_2 gas

2.16 moles of NH_4NO_2 decomposes to give 2.16 moles of N_2 gas

Now we have to calculate the pressure of the gas.

using ideal gas equation,

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

T= temperature of the gas

n = number of moles of gas

R = gas constant = 0.0821 Latm/moleK

Now put all the given values in ideal gas equation, we get pressure of the gas.

P=\frac{nRT}{V}=\frac{(2.16mole)\times (0.0821Latm/moleK)\times (298K)}{10L}=5.285atm

Therefore, the pressure of the gas will be, 5.285 atm

larisa86 [58]3 years ago
3 0

The  change  in pressure in a sealed 10.0L vessel  is 5.28 atm

<u><em>calculation</em></u>

The pressure is calculated using the ideal gas equation

That is   P=n RT

where;

P (pressure)= ?

v( volume) = 10.0 L

n( number of moles)  which is calculated as below

<em>write the equation  for  decomposition  of   NH₄NO₂</em>

NH₄NO₂  →  N₂  +2H₂O

<em>Find the moles of NH₄NO₂</em>

 moles = molarity x volume in liters

= 2.40 l x 0.900 M =2.16 moles

<em>Use the mole ratio to determine the  moles of N₂</em>

that is from equation above  NH₄NO₂:N₂ is 1:1 therefore the moles of N₂ is also =2.16 moles

R(gas constant) =0.0821 l.atm/mol.K

T(temperature)  = 25° c  into kelvin = 25 +273 =298 K

make p the  subject of the formula  by diving both side  by  V

P = nRT/V

p ={ (2.16 moles x 0.0821 L.atm/mol.K  x 298 K) /10.0 L} = 5.28  atm.




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