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Contact [7]
3 years ago
14

Two atoms with the same number of protons that have gained or lost electrons are called

Chemistry
1 answer:
Katyanochek1 [597]3 years ago
3 0

Answer: Anion. The resulting of losing or gaining electrons would be Anion.

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Which of the following atoms releases more energy than oxygen when an electron is added to its valence energy level?
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The answer is b. fluorine (F). This is because fluorine is a more electronegative (electron loving) atom compared to oxygen. It is found on the 7th group of the periodic table, so it has 7 valence electrons. It only needs one more electron to achieve the ideal number of valence electrons which is 8. Oxygen, on the other hand, is in group 6 so it needs 2 more electrons to complete its valency. Helium can't be the answer because it is already in group 8, meaning it is already stable and won't release energy.
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A solution containing less than the equilibrium amount is called ________. a solution containing less than the equilibrium amoun
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<span>I believe it is an unsaturated solution.</span>
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Write a balanced equation for the single-replacement oxidation-reduction reaction described, using the smallest possible integer
jeyben [28]

Answer:

\rm Cl_2 + 2\; KBr \to Br_2 + 2\; KCl.

One chlorine molecule reacts with two formula units of (aqueous) potassium bromide to produce one bromine molecule and two formula units of (aqueous) potassium chloride.

Explanation:

<h3>Formula for each of the species</h3>

Start by finding the formula for each of the compound.

  • Both chlorine \rm Cl and bromine \rm Br are group 17 elements (halogens.) Each
  • On the other hand, potassium \rm K is a group 1 element (alkaline metal.) Each

Therefore, the ratio between \rm K atoms and \rm Br atoms in potassium bromide is supposed to be one-to-one. That corresponds to the empirical formula \rm KBr. Similarly, the ratio between

The formula for chlorine gas is \rm Cl_2, while the formula for bromine gas is \rm Br_2.

<h3>Balanced equation for the reaction</h3>

Write down the equation using these chemical formulas.

\rm ?\; Cl_2 + ?\; KBr \to ?\;Br_2 + ?\; KCl.

Start by assuming that the coefficient of compound with the largest number of elements is one. In this particular equation, both \rm KBr and \rm KCl features two elements each.

Assume that the coefficient of \rm KCl is one. Hence:

\rm ?\; Cl_2 + 1 \; KBr \to ?\;Br_2 + ?\; KCl.

Note that \rm KBr is the only source of \rm K and \rm Br atoms among the reactants of this reaction.

There would thus be one \rm K atom and one \rm Br atom on the reactant side of the equation.

Because atoms are conserved in a chemical equation, there should be the same number of \rm K and \rm Br atoms on the product side of the equation.

In this reaction, \rm Br_2 is the only product with \rm Br atoms.

One \rm Br atom would correspond to 0.5 units of \rm Br_2.

Similarly, in this reaction, \rm KCl is the only product with \rm K atoms.

One \rm K atom would correspond to one formula unit of \rm KCl.

Hence:

\displaystyle \rm ?\; Cl_2 + 1 \; KBr \to \frac{1}{2}\;Br_2 + 1\; KCl.

Similarly, there should be exactly one \rm Cl atom on either side of this equation. The coefficient of \rm Cl_2 should thus be 0.5. Hence:

\displaystyle \rm \frac{1}{2}\; Cl_2 + 1 \; KBr \to \frac{1}{2}\;Br_2 + 1\; KCl.

That does not meet the requirements, because two of these coefficients are not integers. Multiply all these coefficients by two (the least common multiple- LCM- of these two denominators) to obtain:

\displaystyle \rm 1\; Cl_2 + 2 \; KBr \to 1\;Br_2 + 2\; KCl.

7 0
3 years ago
Which of the following sources is considered to be most reliable for scientific
Anarel [89]

Answer:

The answer is D

Explanation:

Pls mark as brainliest

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