Question

How many Faradays of electricity are carried by 1.505×10^23 electronsk​

Answer 1

Mole of electron required by $1.505 *10^{23}$ mole is $2.5* 10 ^{-1}$

• Faraday law expressed how the  change that is been being produced by a current at an electrode-electrolyte interface is related and  proportional to the quantity of electricity  that is been used.

• There is one mole of electron required for 1 Faraday of electricity.

• Avogadro constant is $6.02*10^{23}$

• Mole of electron can be calculated by dividing the number of electron by avogadro's constant.

=$\frac{1.505*10^{23} }{6.02*10^{23} }$

= $2.5* 10^{-1} Faraday of electricity$

Therefore, it requires  $2.5*10^{-1}$ Faraday of electricity for the $1.505 * 10^{23} mole.$

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