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2 years ago

How many Faradays of electricity are carried by 1.505×10^23 electronsk

Chemistry

1 answer:

aksik [14]2 years ago

3 0

Mole of electron required by $1.505 *10^{23}$ mole is $2.5* 10 ^{-1}$

Faraday law expressed how the change that is been being produced by a current at an electrode-electrolyte interface is related and proportional to the quantity of electricity that is been used.

There is one mole of electron required for 1 Faraday of electricity.

Avogadro constant is $6.02*10^{23}$

Mole of electron can be calculated by dividing the number of electron by avogadro's constant.

= $\frac{1.505*10^{23} }{6.02*10^{23} }$

= $2.5* 10^{-1} Faraday of electricity$

Therefore, it requires $2.5*10^{-1}$ Faraday of electricity for the $1.505 * 10^{23} mole.$

Learn more at: brainly.com/question/1640558?referrer=searchResults

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How many Faradays of electricity are carried by 1.505×10^23 electronsk​

How many Faradays of electricity are carried by 1.505×10^23 electronsk