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andrew-mc [135]
3 years ago
11

You begin pouring sodium chloride into a glass of water. For a long time, the sodium chloride just dissolves in the water, but s

uddenly it begins to pile up at the bottom of the glass. Which statement is true?
Chemistry
1 answer:
cricket20 [7]3 years ago
4 0

The options are:

A. The sodium chloride has increased the temperature of the water.

B.he sodium chloride has decreased the temperature of the water.

C.The water is unsaturated.

D. The water is saturated

Answer:

D

Explanation:

An unsaturated solution is one that doesn't have as much solute as it could take. This is the reason why the sodium hydroxide kept dissolving as it was added until at a point where the solution has taken as much solute as it could hold.From that point any additional sodium hydroxide added wont dissolve and would pile up at the bottom of the glass

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ICMP scanning involves in checking for the live systems, which can be done by sending the following ping scan request to a host.
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An ionic bond is formed between
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3 0
2 years ago
Read 2 more answers
Consider the following reaction: 2 Bi(s) + 3 Cl2(g) → 2 BiCl3(s)
Mandarinka [93]

Taking into account the reaction stoichiometry, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 Bi + 3 Cl₂ → 2 BiCl₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Bi: 2 moles
  • Cl₂: 3 moles
  • BiCl₃: 2 moles

The molar mass of the compounds is:

  • Bi: 209 g/mole
  • Cl₂: 70.90 g/mole
  • BiCl₃: 315.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Bi: 2 moles ×209 g/mole=418  g

Cl₂: 3 moles ×70.90 g/mole= 212.7 g

BiCl₃: 2 moles ×315.45 g/mole= 630.9 g

<h3>Mass of Cl₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 630.9 grams of BiCl₃ are formed by 212.7 grams of Cl₂, 3.32 grams of BiCl₃ are formed by how much mass of Cl₂?

mass of Cl_{2} =\frac{3.32 grams of BiCl_{3}x212.7 grams of Cl_{2} }{630.9 grams of BiCl_{3}}

<u><em>mass of Cl₂= 1.119 grams</em></u>

Finally, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

5 0
2 years ago
When 4.21 grams of potassium hydroxide are added to 250 mL of water in a coffee cup calorimeter, the temperature rises by 4.14°C
Schach [20]

Answer:

The molar heat of solution of potassium hydroxide = 57.7 kJ /mol

Explanation:

<u>Step 1:</u> Data given

Mass of potassium hydroxide = 4.21 grams

Volume of water = 250 mL

Temperature rise = 4.14 °C

Density = 1g/mL

Specific heat = 4.184 J/g°C

<u>Step 2:</u> Calculate the heat absorbed by water

q = m*c*ΔT

⇒ with m = the mass of water = 250 grams

⇒ with c= the specific heat of the solution = 4.184 J/g°C

⇒ with ΔT = 4.14 °C

q = 250 * 4.184*4.14 = 4330.4 J

<u>Step 3:</u> Calculate moles of KOH

Moles KOH = Mass KOH / Molar mass KOH

Moles KOH = 4.21 grams / 56.106 g/mol

Moles KOH = 0.075 moles

<u>Step 4:</u> Calculate molar heat of solution

4330.4 J / 0.075 moles = 57738.7 j/mol = 57.7 kJ /mol

(Note that the enthalpy change for the reaction is negative because the reaction is exothermic)

The molar heat of solution of potassium hydroxide = 57.7 kJ /mol

6 0
4 years ago
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