Answer:
Momentum of bullet

momentum of baseball

Explanation:
As we know that momentum is defined as the product of mass and velocity
here we know that
mass of the bullet = 8 gram
velocity of bullet = 340 m/s
momentum of the bullet is given as



Now we have
mass of baseball = 0.2 kg
velocity of baseball = 40 m/s[/tex]
momentum of baseball is given as


Answer:
<h3>(A) The width

m</h3><h3>(B) The new width is

m</h3>
Explanation:
Given :
Focal length 
Maximum aperture
Wavelength
m
(A)
From rayleigh criterion,


rad
From angle formula,

Where
12 m ( given in example )
m

m
(B)
We know that
is proportional to the
and inversely proportional to the 
so we write the new width, here
is 5.5 times larger than above case

m
Is b= acid + base - water + salt.
F= Force
M=Mass
A= acceleration
F=N
Mass= in grams or kilo grams (mostly kg)
A= m/s
Answer:mile
Explanation: heres a hint think aboyt the distance between your house to school