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3 years ago

11

If you had a 30 pound barbell at home and you wanted to compare your muscular endurance to your younger brother's which method w

ould be the best to use.

1 answer:

Helga [31]3 years ago

4 0

Answer:A

Explanation:

Absolute method

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Is the gravitational force between the two objects attractive, repelling, or both? Explain how you know

puteri [66]

Answer: attractive

Explanation:

According to Newton's law of Gravitation, the gravitational force $F$ exerted between two bodies of masses $m1$ and $m2$ and separated by a distance $r$ is equal to the product of their masses and inversely proportional to the square of the distance:

$F=G\frac{(m1)(m2)}{r^2}$

Where:

$G$ is the Gravitational Constant

$m1$ and $m2$ are the masses of the objects

$r$ is the distance between the objects

It should be noted: this force is a central force and is attractive.

6 0

3 years ago

We want to hang a thin hoop on a horizontal nail and have the hoop make one complete small-angle oscillation each 2.0 s. What mu

Mama L [17]

Answer:

Explanation:

Given that the hoop makes one complete oscillation in 2s, this implies that the period of oscillation is 2s

Then,

T = 2s

Let Mass of the thin hoop be M

Let Radius of the hoop be R

Moment of inertial of a hoop is

I = MR²

Period of a physical pendulum of small amplitude is given by

T = 2π √(I / Mgd)

Where,

T is the period in seconds

I is the moment of inertia in kgm²

M is the mass of the hoop

g is the acceleration due to gravity

g = 9.8m/s²

d is the distance from rotational axis to center of of gravity

Therefore, d = R

Then, applying the formula

T = 2π √ (I / MgR)

So, we know that

I = MR²

Then,

T = 2π √( MR² / MgR)

T = 2π √(R/g)

Make R subject of formula

Square both sides

T² = 4π²(R/g)

T²g = 4π²R

Then, R = T²g / 4 π²

Since g = 9.8m/s² and T= 2s

R = 2² × 9.8 / 4π²

R = 0.993m

Then, the radius of the hoop is 0.993m

3 0

3 years ago

The Eiffel Tower is built of wrought iron approximately 300 m tall.Estimate how much its height changes between January (average

Rina8888 [55]

The concepts required to solve this problem are the thermodynamic expressions of expansion and linear expansion.

In mathematical terms the dilation of a body can be expressed as

$\Delta L = L_0 \alpha \Delta T$

Where,

$L_0 =$ Initial Length

$\alpha =$ Thermal coefficient of linear expansion

$\Delta T =$ Change in Length

Our values are given as

$L_0 = 300m$

$T_f = 25\°C$

$T_i = 2\°C$

$\alpha = 12*10^{-6}C^{-1} (Iron)$

Replacing at the equation we have,

$\Delta L = L_0 \alpha \Delta T$

$\Delta L = (300)(12*10^{{-6})(25-2)$

$\Delta L = 0.0828m$

Therefore the change in the height is 8.28cm

3 0

3 years ago

Internal Forces are :

Ugo [173]

Hi Pupil Here's your answer ::

➡➡➡➡➡➡➡➡➡➡➡➡➡

They are always balanced forces since if they are applied on an object the resultant of tgese forces on the object is Zero

So, the option A is the correct. They are always balanced forces.

8 0

3 years ago

Do two electrons placed near each other repel or attract each other?

marishachu [46]

Answer:

the will try to repel

Explanation:

Two electrons will tend to repel each other because both have a negative electrical charge. Two protons will also tend to repel each other because they both have a positive charge. On the other hand, electrons and protons will be attracted to each other because of their unlike charges.

8 0

3 years ago

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