1. A 2500 kg car enters a curve with a radius of 45 m If the car is moving at a speed of 35 m's, what is the
1 answer:
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Answer:
Acceleration of that planet is 30 .
Given:
initial speed of hammer = 0
time = 1 s
distance = 15 m
To find:
Acceleration due to gravity = ?
Formula used:
Distance covered by hammer is given by,
s = ut +
s = distance
u = initial speed of hammer
t = time taken by hammer to reach ground
a = acceleration
Solution:
Distance covered by hammer is given by,
s = ut +
s = distance
u = initial speed of hammer
t = time taken by hammer to reach ground
a = acceleration
u = 0
t = 1 s
s = 15 m
a = g
Thus substituting these value in above equation.
15 = 0 +
g = 15 × 2
g = 30
Thus, acceleration of that planet is 30 .
Answer:
Explanation:
Here two charges are placed at distance "d" apart
now the net value of electric field at some position between two charges will be ZERO
so we will have
electric field due to charge 1 = electric field due to charge 2
Let the position where net field is zero will lie at distance "r" from q1
now we will have
now square root both sides
now we have
so we have