To calculate the velocity of the sound wave, we use this formula:
V = 331 + [0.6*T],
Where V is the velocity and T represents temperature.
When the temperature is 36 degree Celsius, we have
V = 331 + [0.6 * 36]
V = 331 + 21.6 = 352.6
Therefore, V = 352.6 m/s.
Answer:
48 m
Explanation:
Two trains traveling towards one another on a straight track are 300m apart when the engineers on both trains become aware of the impending Collision and hit their brakes. The eastbound train, initially moving at 97.0 km/h Slows down at 3.50ms^2. The westbound train, initially moving at 127 km/h slows down at 4.20 m/s^2.
The eastbound train
First convert km/h to m/s
(97 × 1000)/3600
97000/3600
26.944444 m/s
As the train is decelerating, final velocity V = 0 and acceleration a will be negative. Using third equation of motion
V^2 = U^2 - 2as
O = 26.944^2 - 2 × 3.5 S
726 = 7S
S = 726/7
S1 = 103.7 m
The westbound train
Convert km/h to m/s
(127×1000)/3600
127000/3600
35.2778 m/s
Using third equation of motion
V^2 = U^2 - 2as
0 = 35.2778^2 - 2 × 4.2 × S
1244.52 = 8.4S
S = 1244.52/8.4
S2 = 148.2 m
S1 + S2 = 103.7 + 148.2 = 251.86
The distance between them once they stop will be
300 - 251.86 = 48.14 m
Therefore, the distance between them once they stop is 48 metres approximately.
Answer:
see below
Explanation:
2 Hz, means 2 complete waves are produced in one second, so
2 waves ----- 1 second
2 x 60 -------1 x 60
120 waves ------60 seconds
hope this helps,
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Answer: 4.2 m
Explanation:
The time taken by the tennis ball to cover vertical displacement 1.30 m would be the same time in which ball would cover horizontal distance.
Initial velocity of the ball, u = 8.08 m/s in horizontal direction.
Initial velocity in the vertical direction is 0.
consider upward direction as positive and downward direction as negative. The ball free falls under gravity in the vertical direction.
Using the second equation of motion,
y = u t + 0.5 at²
⇒-1.30 m = 0 + 0.5 ×(-9.8m/s²) t²
⇒t = 0.52 s
There is no external force acting in the horizontal direction, thus horizontal distance covered is:
s = u t ⇒ s = 8.08 m/s × 0.52 s = 4.2 m
Thus, the tennis ball lands 4.2 m far away.
