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Ket [755]
3 years ago
13

Which is the correct mole ratio for aluminum chloride to chlorine in the chemical reaction alcl3 br2 ? albr3 cl2?

Chemistry
2 answers:
weqwewe [10]3 years ago
7 0

Answer : The mole ratio for aluminium chloride to chlorine is, 2 : 3

Explanation :

The given unbalanced chemical reaction is :

AlCl_3+Br_2\rightarrow AlBr_3+Cl_2

First we have to balance the chemical reaction.

In order to balance the chemical reaction, the coefficient 2 is put before AlCl_3\text{ and }AlBr_3 and the coefficient 3 is put before Cl_2\text{ and }Br_2.

The given balanced chemical reaction will be :

2AlCl_3+3Br_2\rightarrow 2AlBr_3+3Cl_2

By the stoichiometry we can say that, 2 moles of AlCl_3 react with 3 moles of Br_2 to give 2 moles of AlBr_3 and 3 moles of Cl_2 as a product.

That means,

The mole ratio between the AlCl_3:Br_2:AlBr_3:Cl_2 are 2:3:2:3 respectively.

Thus, the mole ratio for aluminium chloride to chlorine is, 2 : 3

Lelu [443]3 years ago
5 0
To answer this item what needs to be done is to write the correct and balanced chemical reaction as below.
                                      2AlCl3 + 3Br2 --> 2AlBr3 + 3Cl2
From the chemical reaction above, we can say that every 2 moles of AlCl3 will produce 3 moles of Cl2. Thus, the answer is 2:3. 
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You have 0.21 moles of Al how many atoms do you have
ZanzabumX [31]

Number of atoms : 1.26 x 10²³

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

0.21 moles of Al, so n = 0.21

Number of atoms :

\tt N=0.21\times 6.02\times 10^{23}\\\\N=1.26\times 10^{23}

8 0
2 years ago
How many SO2 molecules are in 1.76 mol of SO2? How many sulfur atoms and oxygen atoms are there?
Ugo [173]

Answer:

1.76 * 6.02*10^23 = 1.05952*10^24

1.05952*2 = 2.11904 *10^24 oxygen and 1.05952*10^24 sulfur atoms

5 0
2 years ago
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bekas [8.4K]
We would be dead. No heart, brain or blood flow <span />
3 0
3 years ago
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3 years ago
3) Calculate the percent by mass of 3.55 g NaCl dissolved in 88 g water.
kotykmax [81]

Answer:

The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%

Explanation:

When a solute dissolves in a solvent, the mass of the resulting solution is a sum of the mass of the solute and the solvent.

A percentage is a way of expressing a quantity as a fraction of 100. In this case, the percentage by mass of a solution is the number of grams of solute per 100 grams of solution and can be represented mathematically as:

Percent by mass=\frac{mass of solute}{mass of solution} *100

In this way it allows to precisely establish the concentration of solutions and express them in terms of percentages.

In this case:

  • mass of solute: 3.55 g
  • mass of solution: 3.55 g + 88 g= 91.55 g

Replacing:

Percentbymass=\frac{3.55}{91.55}*100

Percent by mass= 3.88%

<u><em>The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%</em></u>

5 0
3 years ago
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