Answer:
Step-by-step explanation:
<u><em>Part B:</em></u>
The center of the circumscribed circle around a triangle is equidistant from vertices of that triangle. To find the circumcenter need to draw at least two perpendicular bisectors to the sides of the given triangle. Point of intersect of them is center of the circumscribed circle.
<u><em>Part C:</em></u>
Coordinates of the midpoint of line BC ( y = - 1 ) are
( , ) = <em>( - 2 , - 1 )</em> and the equation of the line ⊥ to BC is <em>x = - 2</em>
Because BC is ║ to x-axis and m∠A is 90° , the center of the circle is midpoint of BC and r = = 4
Answer:
-3x-y=5
y-2z=7
x-4y+z=-9
Step-by-step explanation:
Answer:
,
Step-by-step explanation:
thank my answer
pls mark brilinias
Answer:
The area of the associated sector is
Step-by-step explanation:
step 1
Find the radius of the circle
we know that
The circumference of a circle is equal to
we have
substitute and solve for r
step 2
Find the area of the circle
we know that
The area of the circle is equal to
we have
substitute
step 3
Find the area of the associated sector
we know that
subtends the complete circle of area
so
by proportion
Find the area of a sector with a central angle of
7- 5n=6+6(n+2)
7- 5n=6+6n+12
7 -5n=18+6n
5n-6n=18-7
-11n=11
n=-1