Answer:
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Explanation:
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You need to look at the electronegativity and decide wheter the difference of both of the numbers are significant enough to form a polar bond
Answer:
0.4 moles of water produced by 6.25 g of oxygen.
Explanation:
Given data:
Mass of oxygen = 6.25 g
Moles of water produced = ?
Solution:
Chemical equation;
2H₂ + O₂ → 2H₂O
Number of moles of oxygen:
Number of moles = mass/ molar mass
Number of moles = 6.35 g/ 32 g/mol
Number of moles = 0.2 mol
Now we will compare the moles of oxygen with water:
O₂ : H₂O
1 : 2
0.2 : 2×0.2 = 0.4 mol
0.4 moles of water produced by 6.25 g of oxygen.
Answer:
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Answer:
0.00725 M
Explanation:
Considering for 
Mass = 5.66 g
Molar mass of = 80.043 g/mol
Moles = Mass taken / Molar mass
So,
<u>Moles = 5.66 / 80.043 moles = 0.0707 moles</u>
will dissociate as:
Thus 1 mole of yields 1 mole of ammonium ions. So,
<u>Ammonium ions furnished by = 1 × 0.0707 moles = 0.0707 moles</u>
Considering for 
Mass = 4.42 g
Molar mass of = 149.09 g/mol
Moles = Mass taken / Molar mass
So,
Moles = 4.42 / 149.09 moles = 0.0296 moles
will dissociate as:
Thus 1 mole of yields 3 moles of ammonium ions. So,
<u>Ammonium ions furnished by = 3 × 0.0296 moles = 0.0888 moles</u>
<u>Total moles of the ammonium ions = 0.0707 + 0.0888 moles = 0.1595 moles</u>
Given that:
Volume = 22.0 L
So, Molarity of the 
is:
<u>Molarity = Moles / Volume = 0.1595 / 22 M = 0.00725 M</u>
