Hello!
This is false!! It is the other way around. They usually have a very high melting point. For example table salt is around 800deg C which is approx just under 1500deg F.
Hope this helps. Thank you
2 m/s
Explanation:
The distance to school is 14.4 kilometers which are equal to 14400 meters.
Amy takes 40 minutes which are equal to 40 × 60 = 2400 seconds to arrive at school.
Bill takes 40 + 20 = 60 minutes which are equal to 60 × 60 = 3600 seconds to arrive at school.
Amy’s average speed = distance (m) / time (s)
Amy’s average speed = 14400 m / 2400 s = 6 m/s
Bill’s average speed = 14400 m / 3600 s = 4 m/s
How much faster (in meters/second) is Amy’s average speed for the entire trip?
Amy’s average speed - Bill’s average speed = 6 m/s - 4 m/s = 2 m/s
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average speed
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Answer:
The two steps which results in the release of energy are;
A) Attraction of Na⁺ and Cl⁻<span> to form NaCl
C) </span><span>The addition of an electron to each Cl atom
Explanation:
As we know<em> Born Haber Cycle </em>is helpful in measuring the Lattice Energies of Crystal systems indirectly. So, the formation of NaCl crystal takes place in several steps. Among all steps, The formation of Chloride ions (Electron Affinity) and binding of Na</span>⁺ and Cl⁻ (Lattice Energy) are exothermic in nature, while remaining all steps require energy to proceed (Endothermic).
Reduces from birth till old age is the answer because if you look at the chart, you can see that both the percentages and hours of total sleep time decrease as humans get older.
Answer:
The correct answer is 1.33 x 10⁻⁵ M
Explanation:
The concentration of the stock solution is: C= 1.33 M
In the first dilution, the student added 1 ml of stock solution to 9 ml of water. The total volume of the solution is 1 ml + 9 ml = 10 ml. So, the first diluted concentration is:
C₁= 1.33 M x 1 ml/10 ml = 1.33 M x 1/10 = 0.133 M
The second dilution is performed on C₁. The student added 1 ml of 0.133 M solution to 9 ml of water. Again, the total volume is 1 ml + 9 ml = 10 ml. The second diluted concentration is:
C₂= 0.133 M x 1 ml/10 ml = 0.133 M x 1/10= 0.0133 M
Since the student repeated the same dilution process 3 times more (for a total of 5 times), we have to multiply 5 times the initial concentration by the factor 1/10:
Final concentration = initial concentration x 1/10 x 1/10 x 1/10 x 1/10 x 1/10
= initial concentration x (1/10)⁵
= 1.33 M x 1 x 10⁻⁵
= 1.33 x 10⁻⁵ M
