Answer:
0.00725 M
Explanation:
Considering for 
Mass = 5.66 g
Molar mass of
= 80.043 g/mol
Moles = Mass taken / Molar mass
So,
<u>Moles = 5.66 / 80.043 moles = 0.0707 moles</u>
will dissociate as:
Thus 1 mole of
yields 1 mole of ammonium ions. So,
<u>Ammonium ions furnished by
= 1 × 0.0707 moles = 0.0707 moles</u>
Considering for 
Mass = 4.42 g
Molar mass of
= 149.09 g/mol
Moles = Mass taken / Molar mass
So,
Moles = 4.42 / 149.09 moles = 0.0296 moles
will dissociate as:
Thus 1 mole of
yields 3 moles of ammonium ions. So,
<u>Ammonium ions furnished by
= 3 × 0.0296 moles = 0.0888 moles</u>
<u>Total moles of the ammonium ions = 0.0707 + 0.0888 moles = 0.1595 moles</u>
Given that:
Volume = 22.0 L
So, Molarity of the
is:
<u>Molarity = Moles / Volume = 0.1595 / 22 M = 0.00725 M</u>