If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is
F' = G (5m₁) (2m₂) / d²
F' = 10 Gm₁m₂ / d²
but this is really just F' = 10F. So J is the correct choice.
Answer:
15.7 m/s
Explanation:
The motion of the cannonball is a accelerated motion with constant acceleration g = 9.8 m/s^2 towards the ground (gravitational acceleration). Therefore, the velocity of the ball at time t is given by:
where
u = 0 is the initial velocity
g = 9.8 m/s^2 is the acceleration
t is the time
If we substitute t=1.6 s into the equation, we find the final velocity of the cannonball:
Answer:
1. Identical to that of free fall
Explanation:
As we know that there is same external force acting on an object when it is released in the air which is given as
so here in vertical direction the acceleration is given as
so we will have
so we can say that in vertical direction the acceleration is always same while object is in vertical motion or it is in projectile motion
Answer:
173.45 K
Explanation:
This an Adiabatic process because no energy is lost by thermal conduction on expansion. We will be using this Adiabatic condition and ideal gas equation to solve the question.
From idea gas equation;
PV = nRT
-----(1)
where
P is pressure of the gas
V is volume of the gas
n is number of moles
R is gas constant 8.31441 J K-1 mol-1.
T is temperature in Kelvin
For Adiabatic Condition;
----(2)
Substituting equation(1) into equation(2)
Eliminating the constants and simplify with exponent
Making T₂ the subject of the formula;
The temperature when the initial volume has quadrupled ⇒ V₂ = 4V₁
⇒
Since air is diatomic, we assume k = 1.4
∴
T₂ = 173.45 K