Identify the nuclide produced when thorium-234 decays by beta emission:234 90Th→ 0−1e + ?
1 answer:
<h3>Answer:
234 90Th → 0 -1e + 234 91Pa Explanation:
Given that :
Thorium 234 decays by beta emission Beta emission = 0, - 1 e
234 90Th → 0 -1e + 234 91Pa Hence, when Thorium 234 90 undergoes a beta Decay ; mass number remains the same at 234 while atomic number increases by 1, becoming (90 + 1) = 91 to form a protactinium nuclide.
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Answer:
Molar mass of solute is 183.4g/mol
Explanation:
Using Raoult's law it is possible to find moles of solute, thus:
Where pressure of solution is 53.15 mmHg, pressure of pure solvent is 54.68 mmHg and mole fraction is:
53.15 mmHg = X 54.68 mmHg
<em>0.9720 = X</em>
<em />
Mole fraction of solvent is defined as moles of solvent / total moles.
Moles of solvent are:
286.8g × (1mol / 46.07g) = 6.225 moles of ethanol.
That is:
<em>Where Y are moles of solute.</em>
6.051 + 0.9720Y = 6.225
0.9720Y = 0.174
Y = 0.179 moles of solute
As mass of solute dissolved was 32.83g. Molar mass of solute is:
32.83g / 0.179mol = <em>183.4g/mol</em>