Identify the nuclide produced when thorium-234 decays by beta emission:234 90Th→ 0−1e + ?
1 answer:
<h3>Answer:
234 90Th → 0 -1e + 234 91Pa Explanation:
Given that :
Thorium 234 decays by beta emission Beta emission = 0, - 1 e
234 90Th → 0 -1e + 234 91Pa Hence, when Thorium 234 90 undergoes a beta Decay ; mass number remains the same at 234 while atomic number increases by 1, becoming (90 + 1) = 91 to form a protactinium nuclide.
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Answer: The partial pressure of oxygen in the mixture is 321 mm Hg
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.
Given : = total pressure of gases = 752 mm Hg
= partial pressure of Helium = 234 mm Hg
= partial pressure of nitrogen = 197 mm Hg
= partial pressure of oxygen = ?
Putting in the values we get:
The partial pressure of oxygen in the mixture is 321 mm Hg