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Rudiy27
3 years ago
9

A capaitor has two parallel plates sepearted by 2mm and is connected across a 50V battery. i. What is the electric field between

the plates? ii. What is the surface charge density? iii. How much charge is stored on each plate if the area is 0.1m. iv. Calculate the capacitance. v. How much energy is stored in this capacitor? vi. What is the energy density of the electric field in the capacitor?
Physics
1 answer:
Oduvanchick [21]3 years ago
8 0

Answer:

i E=V/d=50/2*10^-3=25*10^3 N/C

ii It is a (+) and (-)

iii C=εA/d

C=12.56*10^-8 * 0.1/2*10^-4

C=62.83 μF

Q=CV=50*6.283*10^-6

Q=314 μC

iv E=0.5 QV

=0.5(50*314*10^-6)

=7850 μJoule

Explanation:

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v₀ = 280.6 m / s

Explanation:

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Answer:

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A bag of cement has a mass of 62 g. What is the mass of the bag of cement in S.I. units (kg)?
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The mass of this bag of cement in S.I. units (kg) is equal to 0.062 kilograms.

<u>Given the following data:</u>

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To calculate the mass of this bag of cement in S.I. units (kg):

<h3>How to convert to S.I. units.</h3>

In Science, kilograms (kg) is the standard unit of measurement or S.I. units of the mass of a physical object. Thus, we would convert the value of the mass of this bag of cement in grams to kilograms (kg) as follows:

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