Answer:
a) F = 62.2 N
, b) W = 973.2 J
, c) W = -943.3 J and d) W = 0 J
Explanation:
Work is a scalar that is obtained from the scalar product of two vectors, force and displacement. the bold are vectors
W = F.d = F d cos θ
a) As the car travels at constant speed the acceleration is zero
Fx -fr = 0
Fx = fr
Cos θ = Fx / F
F cos θ = fr
F = fr / cos θ
F = 52.7 / cos 32.1
F = 62.2 N
Is the force exerted by the person
b) Let's calculate the thrust force jobs
W = 62.2 17.9 cos 32.1
W = 973.2 J
c) The force of friction that opposes the movement and is on the x-axis
W = fr d cos 180
W = 52.7 17.9 cos 180
W = -943.3 J
d) The force of gravity that is vertical and has an angle of 90º with respect to the displacement
W = mg d cos 90
W = 0 J
Answer:
a)
b)
Explanation:
If the does not slip frm the surface, the friction force will equal to the centripetal force:
Let's call this, <em>eq1.</em>
We also know that angular acceleration is constant, so:
Replacing this on the fs formula:
For the maximum speed before the coin slips, the friction will be and we know that N=m*g. Replacing this values into our previous <em>eq1 </em>result leads to:
Solving for \omega:
Answer: Thermal Energy is energy resulting from the motion of particles; It is a form of kinetic energy and is transferred as heat; Thermal Energy Transfer can occur by three methods: Conduction; Convection; Radiation; Conduction. Conduction is the transfer of thermal energy through direct contact between . particles of a substance.
Explanation:
Answer:
As per Provided Information
- Mass of car m is 1400Kg
- Initial velocity u is 13m/s
- Time taken to stop t is 5 second .
- Final velocity v is 0m/s
we have been asked to determine the force applied to stop the car. First we will calculate the acceleration of the car.
Substituting the value and let's solve it
Now, let's calculate the force applied to stop the car .
Substituting the value we get
Here , negative sign show that the " Force is acting in opposite direction of the motion"
<u>Therefore</u><u>,</u>
- <u>3</u><u>6</u><u>4</u><u>0</u><u> </u><u>Newton</u><u> </u><u>force </u><u>is </u><u> </u><u>required</u><u> </u><u>to</u><u> </u><u>stop</u><u> </u><u>the </u><u>car </u><u>.</u>