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Alexeev081 [22]

3 years ago

7

A charged cloud system produces an electric field in the air near earth's surface. a particle of charge -2.0 × 10-9 c is acted o

n by a downward electrostatic force of 4.3 × 10-6 n when placed in this field. (a) what is the magnitude of the electric field? (b) what is the magnitude of the electrostatic force on a proton placed in this field? (c) what is the gravitational force on the proton? (d) what is the ratio of the electrostatic force to the gravitational force in this case?

1 answer:

defon3 years ago

7 0

Part a)

Magnitude of electric field is given by force per unit charge

$E = \frac{F}{q}$

$E = \frac{4.3 * 10^{-6}}{2 * 10^{-9}}$

$E = 2150 N/C$

Part b)

Electrostatic force on the proton is given as

F = qE

$F = 1.6 * 10^{-19} * 2150$

$F = 3.44 * 10^{-16} N$

PART C)

Gravitational force is given by

$F_g = mg$

$F_g = 1.6 * 10^{-27}*9.8$

$F_g = 1.57 * 10^{-26} N$

PART d)

Ratio of electric force to weight

$\frac{F_e}{F_g} = \frac{3.44 * 10^{-16}}{1.57*10^{-26}}$

$\frac{F_e}{F_g} = 2.2 * 10^{10}$

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3 years ago

A student performs this experiment and measures the bar to have a mass of 150g and length of 36cm. What is the moment of inertia

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Answer:

The moment of inertia of the bar is $45\times10^{-4}\ kg-m^2$

Explanation:

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mass of bar = 150 g

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Using formula of moment inertia

$I=\dfrac{1}{12}Ml^2$

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L = length of the bar

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$I=\dfrac{1}{12}\times150\times10^-3\times36\times10^{-2}$

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Leni [432]

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Rodney is trying out one of Santa's new games that consists of three pieces that blow apart if the wrong key is inserted into th

ch4aika [34]

Answer:

<em>The third piece moves at 6.36 m/s at an angle of 65° below the horizon</em>

Explanation:

Linear Momentum

It's a physical magnitude that measures the product of the velocity by the mass of a moving object. In a system where no external forces are acting, the total momentum remains unchanged regardless of the interactions between the objects in the system.

If the velocity of an object of mass m is $\vec v$ , the linear momentum is computed by

$\displaystyle \vec{P}=m.\vec{v}$

a)

The momentum of the board before the explosion is

$\displaystyle \vec{P}_{t1}=m_t\ \vec{v}_o$

Since the board was initially at rest

$\displaystyle \vec{P}_{t1}=$

After the explosion, 3 pieces are propelled in different directions and velocities, and the total momentum is

$\displaystyle \vec{P}_{t2}=m_1\ \vec{v}_1\ +\ m_2\ \vec{v}_2+m_3\ \vec{v}_3$

The first piece of 2 kg moves at 10 m/s in a 60° direction

$\displaystyle \vec{v}_1=(10\ m/s,60^o)$

We find the components of that velocity

$\displaystyle \vec{v}_1=$

$\displaystyle \vec{v}_1=m/s$

The second piece of 1.2 kg goes at 15 m/s in a 180° direction

$\displaystyle \vec{v}_2=(15,180^o)$

Its components are computed

$\displaystyle \vec{v}_2=(15\ cos180^o,15\ sin180^o)$

$\displaystyle \vec{v}_2=(-15,0)\ m/s$

The total momentum becomes

$\displaystyle P_{t2}=2+1.2+m_3\ \vec{v}_3$

Operating

$\displaystyle P_{t2}=++m_3\ \vec{v}_3$

Knowing the total momentum equals the initial momentum

$\displaystyle P_{t2}=+m_3\ \vec{v}_3=0$

Rearranging

$\displaystyle m_3\ \vec{v}_3=$

Calculating

$\displaystyle m_3\ \vec{v}_3=$

This is the momentum of the third piece

b)

From the above equation, we solve for $\vec v_3$ :

$\displaystyle \vec{v}_3=\frac{1}{3}$

$\displaystyle \vec{v}_3=m/s$

The magnitude of the velocity is

$\displaystyle \vec{v}_3|=\sqrt{2.67^2+(-5.77)^2}=6.36$

And the angle is

$\displaystyle tan\theta =\frac{-5.77}{2.67}=-2.161$

$\displaystyle \theta =-65.17^o$

The third piece moves at 6.36 m/s at an angle of 65° below the horizon

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3 years ago

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grin007 [14]

Answer:

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Explanation:

Acceleration is a quantity that indicates the variation in speed of a moving body as time passes. That is, acceleration relates changes in velocity with the time in which they occur.

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$acceleration=\frac{change in speed}{time}$

In this case:

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Replacing:

$acceleration=\frac{15 \frac{m}{s} }{10 s}$

and solving you get:

<u><em>acceleration= 1.5 </em></u> $\frac{m}{s^{2} }$ <u><em></em></u>

Speed is a quantity that expresses the relationship between the space traveled by an object and the time used for it. This is:

$speed=\frac{distance}{time}$

So the distance can be calculated as:

distance= speed* time

In this case:

speed= 15 m/s
time= 10 s

Replacing:

distance= 15 m/s* 10 s

and solving you get:

<u><em>distance= 150 m</em></u>

<u><em>Its acceleration is 1.5 </em></u> $\frac{m}{s^{2} }$ <u><em> and the distance it has covered is 150 m.</em></u>

8 0

3 years ago