Answer:
Explanation:
Total resistance in the circuit
= EMF / current in the circuit
= 12 / .969
= 12.383 ohm
This resistance consists of 5 identical resistances in series
resistance of each resistor
= 12.383 / 5
= 2.476 ohm .
potential difference on each
= current x resistance of each
= .969 x 2.476
= 2.399 V
= 2.4 V
Answer:
The height of the tree is three (3) deep
Explanation:
It's 3 deep
Under 129, comes 125 and 685;
Under 125, comes 52 : Under 685, comes 511;
Under 52, comes 46 : Under 511, is 601.
This is illustrated below.
129
∧
125,685
|,|
52,511
|,|
46,601
Answer:
V = 11.83 m/s
Explanation:
Given the following data;
Mass = 2000 kg
Force = 10000N
Distance = 14 m
To find the final velocity of the car;
First of all, we would determine the acceleration of the car;
Acceleration = force/mass
Acceleration = 10000/2000
Acceleration = 5 m/s²
Next, we would use the third equation of motion to find the final velocity;
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
S represents the displacement measured in meters.
Substituting into the equation, we have;
V² = 0² + 2*5*14
V² = 0 + 140
V = √140
V = 11.83 m/s
Answer:
Option (C)
Explanation:
From Newton's law of inertia, an object at rest tends to be at rest until there is an external force applied to it.
In the given question, the rock block that fell on the road due to the avalanche contains high mass and high inertia. Due to which the block was not able to move aside. <u>The amount of energy required to push the block aside should be more than the mass of the block</u>. So the block has high inertia value and it will need more force than its inertia value in order to move the block of rock towards the side of the road.
Thus, the correct answer is option (C).
Answer:
d. Imaginary point through which the resultant force of gravity acts on an object
Explanation:
Gravity acting on all particle points of the object, no matter how small they are. As a combination, the center of gravity would denote a single point which substitutes for all the gravity forces on the object.