The apparent weight of a 1.1 g drop of water is 4.24084 N.
<h3>
What is Apparent Weight?</h3>
- According to physics, an object's perceived weight is a characteristic that describes how heavy it is. When the force of gravity acting on an object is not counterbalanced by a force of equal but opposite normality, the apparent weight of the object will differ from the actual weight of the thing.
- By definition, an object's weight is equal to the strength of the gravitational force pulling on it. It follows that even a "weightless" astronaut in low Earth orbit, with an apparent weight of zero, has almost the same weight that he would have if he were standing on the ground; this is because the gravitational pull of low Earth orbit and the ground are nearly equal.
Solution:
N = Speed of rotation = 1250 rpm
D = Diameter = 45 cm
r = Radius = 22.5 cm
M = Mass of drop = 1.1 g
Angular speed of the water = 


Apparent weight is given by


 = 4.24084 N
 = 4.24084 N
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Question:
The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it is efficiently squeezed through the clothes and out the holes in the drum. In a top loader's spin cycle, the 45-cm-diameter drum spins at 1250 rpm around a vertical axis. What is the apparent weight of a 1.1 g drop of water?
 
        
             
        
        
        
Answer:
Kidneys filter our blood,
Explanation:
 Hope this helped :)
 
        
                    
             
        
        
        
Igneous intrusions form when magma cools and solidifies before it can reach the surface. An extrusion consists of extrusive rock; which forms above the surface of the crust.
 
        
             
        
        
        
So looking at the problem, you are going to want to start by finding a common denominator (1) in this case: yb, and combining like terms (2). You are then going to want to multiply both sides by (yb) as the reciprocal to the fractions (3).
1)  3x    6g
     ---- = ---
     y       b
2)  3xb    6gy
     ------ = -----   
     yb       yb
3)       3xb    6gy
  (yb) ------ = -----  
          yb       yb
which becomes: 3xb = 6gy
So after this, things become much more simple, as all you have to do is isolate the (x), which can be done by dividing the entire equation by (3b).
3xb   6gy
----- = -----
3b      3b
where you will then find your answer of:
      2gy
x = -----       (simplified by the GCM of 3)
       b
        
             
        
        
        
Answer:
v = 1.7 m/s
Explanation:
By applying conservation of energy principle in this situation, we know that:
Loss in Potential Energy of Car = Gain in Kinetic Energy of Car
mgΔh = (1/2)mv²
2gΔh = v²
v = √(2gΔh)
where,
v = velocity of car at top of the loop = ?
g = 9.8 m/s²
Δh = change in height = 45 cm - Diameter of Loop
Δh = 45 cm - 30 cm = 15 cm = 0.15 m
Therefore,
v = √(2)(9.8 m/s²)(0.15 m)
<u>v = 1.7 m/s</u>