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Gemiola [76]
2 years ago
6

What is the maximum current value that can be measured with an analog VOM? A. 5 A B. 20 A C. 10 A D. 15 A

Physics
2 answers:
Korvikt [17]2 years ago
8 0
Answer is b to ur question
zvonat [6]2 years ago
4 0

Answer:

B) 20 A

Explanation:

VOM full form is Volt Ohm milliammeter. It indicates that voltage, resistance and the current can be measured using this device. When the variations are very rapid , analog VOM is used instead of a digital VOM.

Using this current ( both A C and DC) can be measured in amperes.

Though the accuracy given by digital devices are more accurate, to identify changes in the circuit being tested and for trouble shooting, analog meters are more preferred.

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An electron with charge −e and mass m moves in a circular orbit of radius r around a nucleus of charge Ze, where Z is the atomic
shepuryov [24]

Answer:

v=\sqrt{\frac{kZe^2}{mr}}

Explanation:

The electrostatic attraction between the nucleus and the electron is given by:

F=k\frac{(e)(Ze)}{r^2}=k\frac{Ze^2}{r^2} (1)

where

k is the Coulomb's constant

Ze is the charge of the nucleus

e is the charge of the electron

r is the distance between the electron and the nucleus

This electrostatic attraction provides the centripetal force that keeps the electron in circular motion, which is given by:

F=m\frac{v^2}{r} (2)

where

m is the mass of the electron

v is the speed of the electron

Combining the two equations (1) and (2), we find

k\frac{Ze^2}{r^2}=m\frac{v^2}{r}

And solving for v, we find an expression for the speed of the electron:

v=\sqrt{\frac{kZe^2}{mr}}

6 0
2 years ago
A $100 cart is moving down an inclined plane at 1.30 m/s. The cart collides with a stationary object and rebounds with a speed o
Rasek [7]

Answer:

0.65  kg*m/s and 0.165 kg*m/s

Explanation:

Step one:

given data

mass m= 0.5kg

initial velolcity u=1.3m/s

final velocity v= 0.97m/s

Required

The change in momentum

Step two:

We know that the expression for impulse is given as

Ft= mv

Ft= 0.5*1.3

Ft= 0.65  kg*m/s

The expression for the change in momentum is given as

P= mΔv

substitute

Pt= 0.5*(1.3-0.97)

Pt= 0.5*0.33

Pt=0.165 kg*m/s

7 0
2 years ago
What component of Star Wars is possible
kolezko [41]
Comparing to current technology, here are some component of star wars that is  possible :

- The drones
Remember the flying drones that could shoot stuff in star wars ? we already made that

- Prosthetic limb
Luke's bionic hand in star wars ? we also already made that

- The probe droids
We used a similar thing when our scientist done an expedition to the moon
7 0
2 years ago
Read 2 more answers
Two horizontal curves on a bobsled run are banked at the same angle, but one has twice the radius of the other. The safe speed (
iren [92.7K]

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}................ii

form i and ii we can write

v^2= \frac{1}{2} u^2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

4 0
3 years ago
Length of table is 1.0m,1.00m and 1.000m.Which one is more accurate?​
natita [175]

Answer:

1.00 m is a more accurate measured length.

Explanation:

Denote length of the table by L.

For L=1.0 m, there is one significant digit after the decimal.

Care 1: When one more significant digit after decimal considered, the exact number can be from 0.95 to 1.05.

So, the possible span of error \Delta E_1= 1.05-0.95= 0.1m

For L=1.00 m, there is two significant digits after the decimal.

Case 2: When one more significant digit after decimal considered, the exact number can be from 0.095 to 1.005.

So, the possible span of error \Delta E_2= 1.005-0.095= 0.01m

Case 3: For L=1.000 m, there is three significant digits after the decimal.

When one more significant digit after decimal considered, the exact number can be from 0.0095 to 1.0005.

So, the possible span of error \Delta E_3= 1.0005-0.0095= 0.001m

As \Delta E_1 >\Delta E_2>\Delta E_3

So, the least error is in the third case when L=1.00m, hence, L= 1.00m is more accurate.

6 0
2 years ago
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