1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gemiola [76]
3 years ago
6

What is the maximum current value that can be measured with an analog VOM? A. 5 A B. 20 A C. 10 A D. 15 A

Physics
2 answers:
Korvikt [17]3 years ago
8 0
Answer is b to ur question
zvonat [6]3 years ago
4 0

Answer:

B) 20 A

Explanation:

VOM full form is Volt Ohm milliammeter. It indicates that voltage, resistance and the current can be measured using this device. When the variations are very rapid , analog VOM is used instead of a digital VOM.

Using this current ( both A C and DC) can be measured in amperes.

Though the accuracy given by digital devices are more accurate, to identify changes in the circuit being tested and for trouble shooting, analog meters are more preferred.

You might be interested in
A student wants to determine the impulse delivered to the lab cart when it runs into the wall. The student measures the mass of
WINSTONCH [101]

The correct answer to the question is : A) The velocity of the cart after it hits the wall.

EXPLANATION:

Before answering this question, first we have to understand impulse.

Impulse of a body is defined as the change in momentum or the product of force with time.

Mathematically impulse = m ( v- u ).

Here, v is the final momentum and u is the initial momentum.

Hence, we need the velocity of the cart after it hits the wall in order to calculate the impulse of the lab cart.

4 0
3 years ago
Read 2 more answers
A cyclist rides at 6.20 m/s through a intersection. A stationary car begins to
Xelga [282]

Answer:

The width of the intersection is 20 meters

Explanation:

The speed with which the cyclist is riding, v₁ = 6.20 m/s

The rate at which the car starts to accelerate, a = 3.844 m/s²

The initial velocity of the car = The car is stationary at the start = 0 m/s

The time at which the cyclist and the car reach the other side of the intersection = The same time;

Let 't' represent the time at which the cyclist and the car both reach the other side of the intersection, we have;

The distance travelled by the cyclist = The distance traveled by the car

∴ v₁ × t = 1/2 × a × t²

Plugging in the values for 'v₁', and 'a' in the above equation, we get;

6.20 × t = 1/2 × 3.844 × t²

∴ 1.922·t² - 6.20·t = 0

∴ t·(1.922·t - 6.20) = 0

t = 0, or t = 6.20/1.922 = 100/31

The time at which the cyclist and the car both reach the other side of the intersection, t = 100/31 seconds

The with of the intersection, w = v₁ × t

∴ w = 6.20 × 100/31 = 100/5 = 20

The width of the intersection, w = 20 meters.

8 0
3 years ago
The best rebounders in basketball have a vertical leap (that is, the vertical movement of a fixed point on their body) of about
nadya68 [22]

Answer:

a) 4.45 m/s

b) 0.9 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -9.81\times 1}\\\Rightarrow u=4.45\ m/s

a) The vertical speed when the player leaves the ground is 4.45 m/s

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-4.45}{-9.81}\\\Rightarrow t=0.45\ s

Time taken to reach the maximum height is 0.45 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1\times 2}{9.81}}\\\Rightarrow t=0.45\ s

Time taken to reach the ground from the maximum height is 0.45 seconds

b) Time the player stayed in the air is 0.45+0.45 = 0.9 seconds

6 0
3 years ago
What is the weight of an object with a mass of 19 kg?
Natalija [7]

Answer:

Every 2.2 kg is 1 pound. So mulitply 19 * 2.2. It's gonna be equal to 41.8

Explanation:

7 0
2 years ago
Read 2 more answers
A scientist kept 1,000 grams of a radioactive material in a container. After 66 days, he observed that 125 grams of the radioact
bixtya [17]
The sample appears to have gone through 3 half-lives
1st half life: 1000 to 500 g
2nd half life: 500 to 250 g
3rd half life: 250 to 125 g
The duration of a half-life, therefore, can be inferred to be 66 ÷ (3) = 22 days. 

After a 4th half life, there will be 125÷2= 62.5 g. 
At this point, an additional 22 days will have passed, for a total of 88 days.
Answer is C. 

8 0
4 years ago
Other questions:
  • Which of the following does not affect gas pressure
    9·1 answer
  • ( Science ) If the sun is far away then why does it look like we get higher than it when we lift a camera high in the sky?
    15·1 answer
  • A tuning fork vibrates 240 times per second. What is the frequency and period?
    9·1 answer
  • If you view a complete free body diagram of a moving object, what two apects of the body's motion will the diagram show?
    14·1 answer
  • A ball is thrown upward. At a height of 10 meters above the ground, the ball has a potential energy of 50 joules (with the poten
    12·1 answer
  • What physics concept is used when designing a motorcycle helmet to protect the head from injury
    15·1 answer
  • How does the law of conservation of energy apply to machines?
    11·2 answers
  • In a bi-prism experiment the eye-piece was placed at a distance 1.5m from the source. The distance between the virtual sources w
    8·1 answer
  • A bullet is shot downward out of a high building with an initial speed of 10 m/s. How fast is the bullet traveling after 5 secon
    5·1 answer
  • Calculate the average maximum height for all three trials when the mass of the bottle is 0.125 kg, 0.250 kg,
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!