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Kobotan [32]
3 years ago
15

A hypothesis is a(n) ______________

Physics
1 answer:
marusya05 [52]3 years ago
6 0

Answer:

It is an educated guess

Explanation:

let me know if the bottom ones need to be answered too.

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The Sears Tower in Chicago is approximately 444 m tall Suppose a book
Reptile [31]

Answer:

A. 66.0 m/s downwards

Explanation:

The Tower has a height of 444m

The book is dropped ,finding the velocity of the book 222m above the ground, means the book will be on air for a  height of 222 m .

Apply the formula for free fall in a horizontal projection as;

h= u²×sin²∅ /2g  where

h= maximum height =222m

g= acceleration due to gravity =9.81 m/s²

∅ = projectile angle = 0

u = velocity of the book

Applying the formula as ;

h= u²×sin²∅ /2g

222 = u²/2*9.81

222*19.62 = u²

4355.64 = u²

√4355.64 = u

65.99 m/s = u

66 m/s  downwards

4 0
3 years ago
If you were to stir salt in water until the salt disappeared, which is the solute?
emmainna [20.7K]
Salt is the solute in that situation

6 0
3 years ago
Read 2 more answers
Consider light that has its third minimum at an angle of 23.3° when it falls on a single slit of width 4.05 μm. Find the wavelen
fredd [130]

Answer:

The wavelength of light is 533 nm.

Explanation:

It is given that,

Width of a single slit, d=4.05\times 10^{-6}\ m

Light has its third minimum at an angle of 23.3° when it falls on a single slit. For destructive interference, the equation for minima is given by:

d\ sin\theta=n\lambda  

Here, n = 3

\lambda=\dfrac{d\ sin\theta}{n}

\lambda=\dfrac{4.05\times 10^{-6}\times sin(23.3)}{3}

\lambda=5.33\times 10^{-7}\ m

\lambda=533\ nm

So, the wavelength of the light is 533 nm. Hence, this is the required solution.

6 0
3 years ago
What supply voltage would be needed to provide a current of 1.2A through a 40 ohm resistor?
Yuki888 [10]
With the use of equation V= IR you are able to solve this probelm

So V=IR
V= 1.2 × 40
V =48v
3 0
3 years ago
Read 2 more answers
Now the same particle is removed from the thread and placed over the center of a charged plate. Are there any conditions under w
labwork [276]

Answer:

changing the direction of the electric potential, we can get the particle to be in balance between the electric force, the weight and the thrust.

Explanation:

When the particle is removed from the wire, friction can be electrically charged, either with negative charges (extra electrons) or with positive charge by electron removal, in this case when the particle is between the condenser plates it experiences a force due to the electric field given by

          ΔV = E d

Where ΔV is the potential difference, d the distance between the plates and E the electric field.

In these cases we can use Newton's second law, where the acceleration is zero

                F_{e} –W + B = 0

                 F_{e} = W –B

                 q E = mg - ρ_air g V

dodne B is the hydrostatic thrust

if  we know the density of the particular

                   ρ_particle = m / V

                   m = ρ_particle V

We replace

                 q E = g v (ρ_particle - ρ_air)

Therefore, by changing the direction of the electric potential, we can get the particle to be in balance between the electric force, the weight and the thrust.

6 0
4 years ago
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