Answer:
A. 66.0 m/s downwards
Explanation:
The Tower has a height of 444m
The book is dropped ,finding the velocity of the book 222m above the ground, means the book will be on air for a height of 222 m .
Apply the formula for free fall in a horizontal projection as;
h= u²×sin²∅ /2g where
h= maximum height =222m
g= acceleration due to gravity =9.81 m/s²
∅ = projectile angle = 0
u = velocity of the book
Applying the formula as ;
h= u²×sin²∅ /2g
222 = u²/2*9.81
222*19.62 = u²
4355.64 = u²
√4355.64 = u
65.99 m/s = u
66 m/s downwards
Salt is the solute in that situation
Answer:
The wavelength of light is 533 nm.
Explanation:
It is given that,
Width of a single slit, 
Light has its third minimum at an angle of 23.3° when it falls on a single slit. For destructive interference, the equation for minima is given by:
Here, n = 3




So, the wavelength of the light is 533 nm. Hence, this is the required solution.
With the use of equation V= IR you are able to solve this probelm
So V=IR
V= 1.2 × 40
V =48v
Answer:
changing the direction of the electric potential, we can get the particle to be in balance between the electric force, the weight and the thrust.
Explanation:
When the particle is removed from the wire, friction can be electrically charged, either with negative charges (extra electrons) or with positive charge by electron removal, in this case when the particle is between the condenser plates it experiences a force due to the electric field given by
ΔV = E d
Where ΔV is the potential difference, d the distance between the plates and E the electric field.
In these cases we can use Newton's second law, where the acceleration is zero
–W + B = 0
F_{e} = W –B
q E = mg - ρ_air g V
dodne B is the hydrostatic thrust
if we know the density of the particular
ρ_particle = m / V
m = ρ_particle V
We replace
q E = g v (ρ_particle - ρ_air)
Therefore, by changing the direction of the electric potential, we can get the particle to be in balance between the electric force, the weight and the thrust.