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Aleksandr-060686 [28]
3 years ago
6

A 430 g soccer ball lying on the ground is kicked and flies off at 25 m/s. If the duration of the impact was .01 s, what was the

average force acting on the ball?
Physics
1 answer:
maw [93]3 years ago
4 0
<h2>The average force acting on the ball is 1075 N in the direction of travel of ball.</h2>

Explanation:

Force is given by rate of change of momentum.

Mass of soccer ball = 430 g = 0.43 kg

Initial velocity = 0 m/s

Final velocity = 25 m/s

Change in momentum = 0.43 x 25 - 0.43 x 0

Change in momentum = 10.75 kg m/s

Time taken = 0.01 s

Rate of change of momentum = Change in momentum ÷ Time

Rate of change of momentum = 10.75 ÷ 0.01

Rate of change of momentum = 1075 N

Force = 1075 N

The average force acting on the ball is 1075 N in the direction of travel of ball.

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Answer:

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OR gate:  only output 1 when either or both of the inputs are 1

NOT gates: takes only one input ad output the opposite of the input

The required circuit should takes two inputs and outputs a 1 if and only if the two inputs are the same signal.

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A  B  not(A) not(B)  A AND B    not(A) AND not(B)   Q

0  0     1          1            0                      1                       1

0   1      1         0            0                     0                       0

1    0     0        1             0                     0                       0

1     1     0       0              1                     0                       1

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