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Aleksandr-060686 [28]
3 years ago
6

A 430 g soccer ball lying on the ground is kicked and flies off at 25 m/s. If the duration of the impact was .01 s, what was the

average force acting on the ball?
Physics
1 answer:
maw [93]3 years ago
4 0
<h2>The average force acting on the ball is 1075 N in the direction of travel of ball.</h2>

Explanation:

Force is given by rate of change of momentum.

Mass of soccer ball = 430 g = 0.43 kg

Initial velocity = 0 m/s

Final velocity = 25 m/s

Change in momentum = 0.43 x 25 - 0.43 x 0

Change in momentum = 10.75 kg m/s

Time taken = 0.01 s

Rate of change of momentum = Change in momentum ÷ Time

Rate of change of momentum = 10.75 ÷ 0.01

Rate of change of momentum = 1075 N

Force = 1075 N

The average force acting on the ball is 1075 N in the direction of travel of ball.

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Answer:

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andrew11 [14]

Answer:

A slow down and stop

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You just said the car is traveling at the speed of 55 m/s.  If I understand this  correctly, that means the car will cover:

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55 meters in the 2nd second,

55 meters in the 3rd second,

55 meters in the 4th second,

55 meters in the 5th second,

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