it cannot be reuse and replaced for long period of time.hope it helps u
Answer:
1030 mph
Explanation:
The new velocity equals the initial velocity plus the wind velocity.
First, in the x (east) direction:
vₓ = 335 mph + 711 cos 19° mph
vₓ = 1007 mph
And in the y (north) direction:
vᵧ = 0 mph + 711 sin 19° mph
vᵧ = 231 mph
The net speed can be found with Pythagorean theorem:
v² = vₓ² + vᵧ²
v² = (1007 mph)² + (231 mph)²
v ≈ 1030 mph
The question is incomplete, the options are;
RI^2
I^2/R
R/I^2
R/V^2
RV^2
V^2/R
VI
VIR
Select all that apply
Answer:
P=RI^2
P=V^2/R
P=VI
Explanation:
Power is the rate at which energy is changing in a circuit. It is shown by the formulas outlined above from the group of answer choices. Since the current (I), voltage (V), and resistance (R) were mentioned in the question, any of three three formulas could be used to obtain the power drawn by the conductor.
speed of the car = 27 m/s
speed of truck ahead = 10 m/s
relative speed of car with respect to truck

relative deceleration of car

now the distance before they stop with respect to each other is given by



so it will come at the same speed of truck after 20.6 m distance and hence it will not hit the truck as the distance of the truck is 25 m from car
Part b)
Distance traveled by car before it stops is given by



so it will stop after it will cover total 52.1 m distance
Part c)
time taken by the car to stop



now the distance covered by truck in same time

now after the car will stop its distance from the truck is

<em>so the distance between them is 11.5 m</em>