Answer:
distance = 27.95 [mi]
Explanation:
in order to solve this problem, we must use the appropriate conversion factor, i.e. a conversion factor that relates the kilometers to Miles.
![1 [km] = 0.6214 [mill]\\45[km]*0.6212[\frac{mill}{1km} ]=27.95 [mill]](https://tex.z-dn.net/?f=1%20%5Bkm%5D%20%3D%200.6214%20%5Bmill%5D%5C%5C45%5Bkm%5D%2A0.6212%5B%5Cfrac%7Bmill%7D%7B1km%7D%20%5D%3D27.95%20%5Bmill%5D)
Answer:
inversely proportional to the temperature
Explanation:
Wein's displacement law states the wavelength at which Earth’s emitted radiation is maximum <u>is inversely proportional to the temperature</u> at which the wavelength of the Sun’s emitted radiation peaks.
λmax 
where,
λmax is the maximum wavelength
b is a constant of proportionality called Wien's displacement constant (b = 2.897 × 10⁻³ m.K)
T is the absolute temperature in kelvins
Answer:
Because their properties like conductivity, electronic configuration and ionization lies in between the metals and nonmetals.
Explanation:
There are a total of six elements that fall in the category of semiconductors.
Namely these are boron, silicon, germanium, arsenic, antimony, and tellurium.
These elements look like metals i.e. are lustrous but do not conduct electricity so well like a metal does.
Their chemical behavior falls between that of metals and nonmetals. For example, the pure metalloids form covalent crystals like the nonmetals, but like the metals, they generally do not form mono-atomic anions.
Answer:
B, the internet serves to provide people with more insightful explanations on things that they have not experienced yet but want to find out more on.
Answer:
6.45×10¯²⁶ J
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 97.3 MHz
Energy (E) =?
Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:
1 MHz = 1×10⁶ Hz
Therefore,
97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz
97.3 MHz = 9.73×10⁷ Hz
Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.
Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:
Frequency (f) = 9.73×10⁷ Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 6.63×10¯³⁴ × 9.73×10⁷
E = 6.45×10¯²⁶ J
Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J
