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Leona [35]
3 years ago
10

Gulls are often observed dropping clams and other shellfish from a height to the rocks below, as a means of opening the shells.

If a seagull drops a shell from rest at a height of 16 m, how fast is the shell moving when it hits the rocks
Physics
1 answer:
kumpel [21]3 years ago
8 0

Answer:

v = 17.71 m / s

Explanation:

We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity

                v² = v₀² - 2 g (y -y₀)

                v² = 0 - 2g (y -y₀)

when it hits the stone the height is zero and part of the height of the seagull I

              v² = 2g y₀

              v = Ra (2g i)

let's calculate

              v =√ (2 9.8 16)

              v = 17.71 m / s

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