300 mL of NaCl solution contains
NaCl.
Further Explanation:
The concentration is the proportion of substance in the mixture. The most commonly used concentration terms are as follows:
1. Molarity (M)
2. Molality (m)
3. Mole fraction (X)
4. Parts per million (ppm)
5. Mass percent ((w/w)%)
6. Volume percent ((v/v)%)
7. Mass per volume percent ((w/v)%)
Mass per volume percent is defined as the amount of solute dissolved in a given volume of the solvent, multiplied by 100 %.
The formula to calculate the mass per volume percent of the solution is as follows:

Given information:
A 2.0 % (m/v) NaCl solution
To calculate:
Amount of NaCl in 300 mL of the solution
Firstly, we have to find out the amount of NaCl that is present in 2.0 % NaCl solution.
A 2.0 % NaCl solution indicates that 2 g of NaCl is dissolved in 100 mL of the solution.
So the amount of NaCl in 300 mL of the solution is calculated as follows:

So 300 mL of NaCl solution contains 6 g of NaCl.
Learn more:
1. What is the mass of 1 mole of viruses: brainly.com/question/8353774
2. Determine the moles of water produced: brainly.com/question/1405182
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Concentration terms
Keywords: 2.0 %, NaCl, solution, concentration, proportion, substance, mixture, molarity, molality, mole fraction, parts per million, mass percent, volume percent, mass per volume percent, m, v, m/v, m/v %, 6 g.