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3 years ago

What is [OH-] in a solution that has [H3O+] = 2 x 10-4 ?

Chemistry

1 answer:

ipn [44]3 years ago

5 0

Answer:

The OH- in a solution which has a H3O+ of 2x10^-4 M is 5x10^-11 M. This is because the pOH of that solution is 10.3 since it has a pH of 3.7.

hope it helped

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a bond where electrons are transferred from one atom to another, resulting in charge imbalance in each atom. a bond where electr

Illusion [34]

Answer:

1. A bond where electrons are transferred from one atom to another, resulting in charge imbalance in each atom is called ionic bonding.

2. A bond where electrons are equally shared, resulting in equal numbers of electrons orbiting each atom is called non-polar covalent bond.

3. A bond where electrons are unequally shared, resulting in more electrons orbiting certain atoms than others is called a polar covalent bond.

4. A bond where the electronegativity differences between the atoms within a molecule result in the partially positive atoms of one molecule attracting the partially negative atoms of other molecules is called polar bond and it is part of the covalent bonds.

Explanation:

1. In ionic bonding process, electrons are enterely transferred from one atom to another either losing or gaining negatively charged electrons, and the reacting atoms form ions. A charge imbalance is caused then by the oppositely charged ions, when attracted to each other by electrostatic forces, the basis of the ionic bond.

2. A non-polar covalent bond is occurs when two atoms have same electron afinity to share their electrons equally. The closer the values of their electron affinity, the stronger the attractionis. This is created in diatomic elements or gas molecules.

3. A polar covalent bond is a type of chemical bond where two electrons are unequally shared between two atoms, electrons are not equally shared because one atom spends more time with the electrons than the other atom, resulting in more electrons orbiting certain atoms than others.

4. The polar bond is a type of covalent bonds. This bonds depends on atoms´electronegativity differences. If an atom is less electronegative, it means that the electron distribution or charge is unevenly distributed or polarized and then it becomes partially positive.

8 0

4 years ago

How to do limiting reagents for chemistry?

gavmur [86]

Balance the chemical equation for the chemical reaction.
Convert the given information into moles.
Use stoichiometry for each individual reactant to find the mass of product produced.
The reactant that produces a lesser amount of product is the limiting reagent.
The reactant that produces a larger amount of product is the excess reagent.
To find the amount of remaining excess reactant, subtract the mass of excess reagent consumed from the total mass of excess reagent given.

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3 years ago

Where is most of the mass found in an atom

IgorLugansk [536]

massive livand that sarah or someone is how u do it

7 0

3 years ago

Read 2 more answers

How many grams of KCl is needed to make .75 L of a 1 M solution of KCl?

Zielflug [23.3K]

Answer:

The answer to your question is 25.9 g of KCl

Explanation:

Data

Grams of KCl = ?

Volume = 0.75 l

Molarity = 1 M

Formula

$Molarity = \frac{number of moles}{volume}$

Solve for number of moles

$Number of moles = Molarity x volume$

Substitution

Number of moles = 1 x 0.75

Simplification

Number of moles = 0.75 moles

Molecular mass KCl = 39 + 35.5 = 34.5

Use proportions to find the grams of KCl

34.5 g of KCl ---------------- 1 mol

x ---------------- 0.75 moles

x = (0.75 x 34.5) / 1

x = 25.9 g of KCl

3 0

3 years ago

To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?

poizon [28]

We know that to relate solutions of with the factors of molarity and volume, we can use the equation: $M_{1} V_{1} = M_{2} V_{2}$

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M $H_{2} SO_{4}$ is the left side of the equation. Then we have:

$(18 M)(0.050 L)=(4.35M) V_{2}$

We can then solve for $V_{2}$ :

$V_{2}= \frac{(18M)(0.05L)}{4.35M}$ and $V_{2} =0.21 L$ or $210 mL$

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.

7 0

4 years ago