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Y_Kistochka [10]
3 years ago
15

Chloe wants to lighten the color of her dark hair, which will require the use of both haircolor and hydrogen peroxide. hydrogen

peroxide (h2o2) is an example of a(n):
Chemistry
1 answer:
bearhunter [10]3 years ago
7 0

The answer is developer .

Chloe wants to lighten the color of her dark hair, which will require the use of both hair color and hydrogen peroxide.

Hydrogen peroxide (H₂O₂) is an example of a most commonly used developer in hair color.

Hydrogen peroxide lighten hair color, as it can dissolve darker pigment. According to the  natural hair color and the length of time a person will leave hydrogen peroxide on  hair,  hair can turn somewhere on the color spectrum between caramel, orange and yellow.





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Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3?
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Answer:

65.08 g.

Explanation:

  • For the reaction, the balanced equation is:

<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.

  • Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:

<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>

<u><em>Using cross multiplication:</em></u>

2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.

0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.

∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃  = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.

<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol ) = <em>65.08 g.</em>

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