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3 years ago

What is the mass of 5.22×10^21 platinum atoms??

Chemistry

2 answers:

antiseptic1488 [7]3 years ago

7 0

Answer:

1.69g

Explanation:

To solve the problem you need to know the Avogadro´s number and the molar mass of the Platinum.

The Avogadro´s number is $6.022*10^{23}\frac{atoms}{mol}$ . For the platinum it means that there are $6.022*10^{23}\frac{atoms}{mol}$ atoms of platinum for each mol.

And the molar mass for the platinum is $195.084\frac{g}{mol}$ , that is the mass in grams of each mol of platinum.

So, with this information we can solve the problem as follows:

$5.22*10^{21}atomsofPt*\frac{1molofPt}{6.022*10^{23}atomsofPt}*\frac{195.084g}{1molofPt}=1.69g$ of Pt

sp2606 [1]3 years ago

4 0

Atomic mass platinum = <span>195.084 a.m.u

195.084 g -------------- 6.02x10</span>²³ atoms
?? g -------------------- 5.22x10²¹ atoms

( 5.22x10²¹) x 195.084 / 6.02x10²³ => 1.691 g

hope this helps!

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1 year ago

A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?

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Answer:

At -13 $^{0}\textrm{C}$ , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

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$V_{1}$ and $V_{2}$ are initial and final volume respectively.

$T_{1}$ and $T_{2}$ are initial and final temperature in kelvin scale respectively.

Here $P_{1}=150.0kPa$ , $V_{1}=1.75L$ , $T_{1}=(273-23)K=250K$ , $P_{2}=210.0kPa$ and $V_{2}=1.30L$

Hence $T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}$

$\Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}$

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3 years ago

What is the missing value

Korvikt [17]

Answer:

Explanation:

The pattern here may be hard to find at first, but it's this: the number in the middle of the triangle = (number at lower left corner of triangle x number at upper vertex of triangle) + (number at upper vertex of triangle x number at lower right corner of triangle).

Thus, for the missing value...

Missing value = (3x8) + (8x6) = 24+48 = 72.

Could you tell me what concept in chemistry relates to this? I'm interested.

Also check out stylesben's answer. Seems like there's several ways of doing this.

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2 years ago

Read 2 more answers

In the laboratory a student determines the specific heat of a metal. She heats 19.6 grams of zinc to 98.37°C and then drops it i

fgiga [73]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc = 98.37 °C

Initial temperature of water = 24.16 °C

Final temperature of water (and zinc) = 25.70 °C

Specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate Specific heat of zinc

Heat lost by zinc = heat won by water

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

Qzinc = -Qwater

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

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3 years ago