Question

What is the mass of 5.22×10^21 platinum atoms??

Answer 1

Answer:

1.69g

Explanation:

To solve the problem you need to know the Avogadro´s number and the molar mass of the Platinum.

The Avogadro´s number is $6.022*10^{23}\frac{atoms}{mol}$. For the platinum it means that there are $6.022*10^{23}\frac{atoms}{mol}$ atoms of platinum for each mol.

And the molar mass for the platinum is $195.084\frac{g}{mol}$, that is the mass in grams of each mol of platinum.

So, with this information we can solve the problem as follows:

$5.22*10^{21}atomsofPt*\frac{1molofPt}{6.022*10^{23}atomsofPt}*\frac{195.084g}{1molofPt}=1.69g$ of Pt

Answer 2

Atomic mass platinum = 195.084 a.m.u

195.084 g -------------- 6.02x10²³ atoms
?? g -------------------- 5.22x10²¹ atoms

( 5.22x10²¹) x 195.084 / 6.02x10²³ => 1.691 g

hope this helps!