The answer is 110., but round accordingly
Answer:p-hydroxybenzaldehyde is stronger acid to phenol
para-cyanophenol is stronger acid to meta-cyanophenol
o-fluorophenol is stronger acid to p-fluorophenol.
Explanation:
The PKa tool relative to Ph are used to contrast the pairs.
The pKa of phenol is 10. The pKa of p-hydroxybenzaldehyde is 9.24
The pKa for meta-cyanophenol is 8.61 and the pKa for para-cyanophenol is 7.95.
The pKa value of o-fluorophenol is 8.7, while that of the p-fluorophenol is 9.9. It's obvious that the inductive effect is more dominant at ortho-position, which results in a more acidic nature
The pKa is the pH value at which a chemical species will accept or donate a proton. The lower the pKa, the stronger the acid and the greater the ability to donate a proton in aqueous solution.
Answer:
8306.76
Explanation:
you just calcuate 8.12 x 1023 and that will give you the answer
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Answer : The non-bonding and bonding electrons are 10 and 14 respectively.
Explanation :
Electron-dot structure : It is also known as Lewis-dot structure. It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
The given molecule is, Acetyl chloride 
Carbon has '4' valence electrons, hydrogen has '1' valence electron, oxygen has '6' valence electrons and chlorine has '7' valence electrons.
Therefore, the total number of valence electrons in = 2(4) +3(1) +6 +7 = 24
According to electron-dot structure, there are 14 number of bonding electrons ans 10 number of non-bonding electrons.
The electron-dot structure of is shown below.
