1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
o-na [289]
3 years ago
11

In an equimolar mixture of o2 and n2, are the mass fractions equal?

Chemistry
1 answer:
nika2105 [10]3 years ago
4 0

Answer:

No

Explanation:

The mass fraction is defined as:

w_{i}=\frac{m_{i} }{m_{t} }

where:

  • wi: mass fraction of the substance i
  • mi: mass of the substance i
  • mt: total mass of the system

<u><em>The mass fraction of two substances (A and B), will be the same, ONLY if the mass of the substance A (mA) is the same as the mass of the substance B (mB).</em></u>

An equimolar mixutre of O2 and N2 has the same amount of moles of oxygen and nitrogen, just to give an example let's say that the system has 1 mole of O2 and 1 mole of N2. Then using the molecuar weigth of each of them we can calculate the mass:

mA= 1 mole of O2 * 16 g/1mol = 16 g

mB=1 mole of N2 *28 g/1mol=28 g

As mA≠mB then the mass fractions are not equal, so the answear is NO.

You might be interested in
A sample of the chiral molecule limonene is 79% enantiopure. what percentage of each enantiomer is present? what is the percent
Degger [83]

Answer :  The % of (+) limonene isomer = 79%


                The % of (-) limonene isomer = 0%


                The % of enantiomeric excess = 58%


Explanation :   Enantiomeric excess (ee) is the measurement of purity used for chiral substances.


Given,


% of pure limonene enantiomer = The % of (+) limonene isomer = 79%


Therefore, The % of (-) limonene isomer = 0%


Formula used :  

\%(+)\text{ isomer}=\frac{ee}{2}+50\%


Where,         ee → enantiomeric excess


Now, put all the values in above formula, we get the value of enantiomeric excess (ee).


     {ee}=\frac{\%(+)-50\%}{2}


            =\frac{79\%-50\%}{2}


              = 58%



7 0
3 years ago
Read 2 more answers
A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Evgesh-ka [11]

Answer:

The answer to your question is   P2 = 0.78 atm

Explanation:

Data

Temperature 1 = T1 = 263°K                 Temperature 2 = T2 = 298°K

Volume 1 = V1 = 24 L                             Volume 2 = V2 = 35 L

Pressure 1 = P1 = 1                                  Pressure 2 = P2 = ?

Process

1.- To solve this problem use the Combined gas law

                          P1V1/T1 = P2V2/T2

-Solve for P2

                           P2 = P1V1T2 / T1V2

-Substitution

                          P2 = (1)(24)(298) / (263)(35)

-Simplification

                          P2 = 7152 / 9205

-Result

                          P2 = 0.777

   or                    P2 = 0.78 atm

5 0
3 years ago
For all of the following questions 20.00 mL of 0.200 M HBr is titrated with 0.200 M KOH.
HACTEHA [7]

Answer :

The concentration of H^+ before any titrant added to our starting material is 0.200 M.

The pH based on this H^+ ion concentration is 0.698

Explanation :

First we have to calculate the concentration of H^+ before any titrant is added to our starting material.

As we are given:

Concentration of HBr = 0.200 M

As we know that the HBr is a strong acid that dissociates complete to give hydrogen ion H^+ and bromide ion Br^-.

As, 1 M of HBr dissociates to give 1 M of H^+

So, 0.200 M of HBr dissociates to give 0.200 M of H^+

Thus, the concentration of H^+ before any titrant added to our starting material is 0.200 M.

Now we have to calculate the pH based on this H^+ ion concentration.

pH : It is defined as the negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

pH=-\log (0.200)

pH=0.698

Thus, the pH based on this H^+ ion concentration is 0.698

3 0
3 years ago
What is the mass of 5.84 × 10^21 atoms of xenon?
podryga [215]

Answer:

5.84e+21

Explanation:

8 0
2 years ago
The pictured compound has which of the following bonds?
Veseljchak [2.6K]

Answer: There are C - C  bonds and C - H bonds.

trust me! I took a test with this question and got 100! :)

6 0
3 years ago
Other questions:
  • 8.00ml of 1.25M lithiukm hydroxide is reacted with sulfuric acid. It is found that 52.87mL of the sulfuric acid is required to c
    10·1 answer
  • Need help ASAP!! What is a function mitochondrion
    15·1 answer
  • Which of the following is a balanced chemical equation?
    8·1 answer
  • What are mixtures that have evenly mixed groups of particles that do not settle out called?
    8·1 answer
  • Aaleyah learned that astronomers use different properties, such as their
    6·1 answer
  • What is Sulfurs electron configuration?
    9·1 answer
  • Explain how the words are alike and different
    10·1 answer
  • 5. (10 Points) The volume of air in the lungs of a typical human is 6.0 L.
    11·1 answer
  • Fove seconds without gravity would be detrimental to earth.<br>A.True<br>B.False​
    11·1 answer
  • If there is no change in concentrations, why is the equilibrium state considered dynamic?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!