Answer:
C₆H₁₅O₃N + H₂O ⇄ C₆H₁₅O₃NH⁺ + OH⁻
Explanation:
A Bronsted-Lowry base is defined as a substance than can accept a proton, H⁺.
When triethanolamine, C₆H₁₅O₃N, reacts with water, H₂O, as follows:
<h3>C₆H₁₅O₃N + H₂O ⇄ C₆H₁₅O₃NH⁺ + OH⁻</h3><h3 />
As you can see, in this reaction, triethanolamine is able to accept a proton that is given for the water.
The Coefficients would be:
Hg(CO3)2: 1
AgCl: 4
HgCl4: 1
Ag2CO3: 2
How do we know this?
Because if we look at the coefficent for the first compound, Hg(CO3)2, That means in total we have one Hg and 2 CO3's.
IF the coefficient is 4 for the next compound, AgCl, there are 4 Ag's and 4 Cl's.
Those were the REACTANTS to our equation. Now looking at the arrow, HgCl4 and Ag2CO3 are our PRODUCTS, or, what is FORMED from Hg(CO3)2 and AgCl. So, we need to make sure that they are equal, to obey the law of conservation of mass. So in simpler terms, if we have 4 Cl's on the reactant side, we need 4 on the products side.
So, if we had the coefficient of 1 for HgCl4, this makes sense, because on the products side we had 1 Hg, and 4 Cl's. With the coefficient of 1, we have 1 Hg and 4 Cl's on the products side, as well!
And if we had the coefficient of 2 for Ag2CO3, we would have 4 Ag's total and 2 CO3s, which matches on the reactants side, for we have two CO3's and 4 Ag's.
I hope I could help!
<span>d. to reduce indigestion </span>
<span>Acids actually break down digestion also the rest on the list are all acids.</span>
Answer:
The strength of the intermolecular forces in isopropyl alcohol are in between water and acetone, but probably closer to acetone because the water took much longer to evaporate. ... Acetone does not participate in hydrogen bonding, so its intermolecular forces are comparatively weaker, and it evaporates most quickly.
Explanation:
Mud and muddy water both are an example of suspension
suspension are heterogenous mixture containing solid solute particles not dissolved but are suspended in the medium
