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3 years ago

Is mud colloid or suspension?? what about muddy water????

Chemistry

2 answers:

vlada-n [284]3 years ago

5 0

Mud and muddy water both are an example of suspension

SCORPION-xisa [38]3 years ago

3 0

Mud and muddy water both are an example of suspension
suspension are heterogenous mixture containing solid solute particles not dissolved but are suspended in the medium

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As changes in energy levels of electrons increase, the frequencies of atomic line spectra they emit ___?

Tju [1.3M]

Ans: As changes in energy levels of electrons increase, the frequencies of atomic line spectra they emit will increase.

The energy (E) is related to the frequency (ν) by the following equation:

E = hν

where h = planck's constant

The change in energy i between levels is:

ΔΕ = h(Δν) -----(1)

Based on the above equation, as the changes in energy levels increase, the frequency of emitted radiation will also increase.

6 0

3 years ago

How much percent of shops are in the city? How about in the country?

kolezko [41]

Answer:

I would say there would be 5-10% in a city, and maybe 10-20% in the country. It mainly varies depending on how big the city is, how many people/districts there are, and the size of the country, which makes it hard to give a certain percent of shops, as there may be small businesses included as well or new shops being built.

Hope this helps! This was pretty confusing for me as well so i hope the answer is alright (×﹏×)

7 0

2 years ago

if 100. mL of 0.800 M Na2SO4 is added to 200. mL of 1.20 M NaCl, what is the concentration of Na+ ions in the final solution? As

Black_prince [1.1K]

Compounds Na₂SO₄ and NaCl are mixed together are we are asked to find the concentration of Na⁺ in the mixture
Na₂SO₄ ---> 2 Na⁺ + SO₄³⁻

1 mol of Na₂SO₄ gives out 2 mol of Na⁺ ions

the number of Na₂SO₄ moles added - 0.800 M/1000 * 100 ml
= 0.08 mol
therefore number of Na⁺ ions from Na₂SO₄ = 0.08 * 2 = 0.16 mol

NaCl ----> Na⁺ + Cl⁻
1 mol of NaCl gives 1 mol of Na⁺ ions
number of NaCl moles added = 1.20 M/1000 * 200 ml
= 0.24 mol
number of Na⁺ ions from NaCl = 0.24 mol

total number of Na⁺ ions in the mixture = 0.16 mol + 0.24 mol = 0.4 mol
as stated the volumes are additive,
therefore total volume = 100 ml + 200 ml = 300 ml
the concentration of Na⁺ ions = number of moles / volume
= 0.4 mol/ 0.3 dm³
concentration of Na⁺ = 1.33 mol/dm³

5 0

3 years ago

What is the gulf stream. a surface current a deep current a river a climate event

guapka [62]

I think it’s a climate event

5 0

3 years ago

After a reaction, a new compound contains 0.73 g Mg and 0.28 g N. What is the empirical formula of this compound?

FromTheMoon [43]

Answer:

Mg₃N₂

Explanation:

The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound. Using molecular mass of Mg (24,305g/mol) and mass of nitrogen (14,006g/mol), moles of each element are:

0,73g × (1mol / 24,305g) = 0,03 moles of Mg

0,28g × (1mol / 14,006g) = 0,02 moles of N

Dividing each value in 0,01 to obtain natural numbers:

0,03 moles of Mg / 0,01 = 3

0,02 moles of N / 0,01 = 2.

Thus, empirical formula is: Mg₃N₂

I hope it helps!

5 0

3 years ago