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BabaBlast [244]
3 years ago
15

Is mud colloid or suspension?? what about muddy water????

Chemistry
2 answers:
vlada-n [284]3 years ago
5 0
Mud and muddy water both are an example of suspension
SCORPION-xisa [38]3 years ago
3 0
Mud and muddy water both are an example of suspension
suspension are heterogenous mixture containing solid solute particles not dissolved but are suspended in the medium
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Is alka seltzer and acid or a base or netural
fiasKO [112]

Answer:

Base

Explanation:

Why is Alka-Seltzer a base?

Alka-Seltzer contains sodium bicarbonate and citric acid. The sodium citrate acts as an antacid. Excess sodium bicarbonate from the Alka-Seltzer acts to neutralize base.

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2 years ago
Where would you expect to find an element with the greatest electronegativity?
beks73 [17]
As you move from left to right of the periodic table, the element becomes more negative.
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3 years ago
If Steve throws a football 57 meters in 3 seconds, what is the average speed of the football?​
sattari [20]

Answer:

19 m/s

Explanation:

57/3

7 0
2 years ago
A bond in which one atom contributes both bonding electrons to a covalentbond
yKpoI14uk [10]
<h3>Answer:</h3>

A coordinate bond

<h3>Explanation:</h3>
  • A chemical bond is a force of attraction between two or more atoms of elements.
  • Covalent bond is a type of chemical bond that occurs between non-metal atoms.
  • It occurs as a result of sharing of electrons between the non-metal atoms.
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4 0
3 years ago
Sodium hydrogen carbonate NaHCO3, also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Ac
olga2289 [7]

Answer:

1.4952 grams of sodium bicarbonate she  would need to ingest to neutralize this much HCl.

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

Moles of hydrochloric acid = n

Volume of hydrochloric acid solution = 200.0 mL = 0.200 L

Molarity of the hydrochloric acid = 0.089 M

n=0.089 M\times 0.200 L=0.0178 mol of HCL

HCl(aq)+NaHCO_3(aq)\rightarrow NaCl(aq)+H_2O(l)+CO_2(g)

According to reaction, 1 mole of HCl is neutralized by 1 mole of sodium bicarbonate.

Then 0.0178 moles of HCl wil be neutralized by :

\frac{1}{1}\times 0.0178 mol=0.0178 mol of sodium bicarbonate

Mass of 0.0178 moles of sodium bicarbonate:

0.0178 mol × 72 g/mol = 1.4952 g

1.4952 grams of sodium bicarbonate she  would need to ingest to neutralize this much HCl.

8 0
3 years ago
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