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kotegsom [21]
2 years ago
13

What is the surface temperature of a distant star having a peak wavelength of 475 nm?

Physics
1 answer:
ladessa [460]2 years ago
3 0

Answer:

Explanation:

Given that,

The peak wavelength is

λp = 475nm

Then, we want to find the temperature,

From Wein's displacement law,

When the maximum is evaluated from the Planck radiation formula, the product of the peak wavelength and the temperature is found to be a constant (k = 2.898 ×10^-3 mK)

So, applying this we have

λp•T = 2.898 ×10^-3

T = 2.898 × 10^-3 / λp

T = 2.898 × 10^-3 / 475 × 10^-9

T = 6101.05 K

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An elaborate pulley consists of four identical balls at the ends of spokes extending out from a rotating drum. A box is connecte
Klio2033 [76]

Answer:

its speed will be less than V

Explanation:

When the ball falls a distance d, its final kinetic energy plus rotational kinetic energy of the drum equals its initial potential energy.

K = U

With its speed V at the end of d, we have

1/2mV² + 1/2Iω² = mgd where I = rotational inertia of drum and balls, ω = angular speed of drum and balls and m = mass of box

1/2mV² + 1/2Iω² = mgd

1/2mV² = mgd - 1/2Iω²

V² = [2(mgd - 1/2Iω²)/m]

V = √[2(mgd - 1/2Iω²)/m]

When the four balls are moved inward closer to the drum, their rotational inertia increases and also its angular speed which thus causes an increase in rotational kinetic energy. But, since the box still falls the same distance of d, its final kinetic energy plus rotational kinetic energy of the drum plus balls still equals its initial potential energy

K = U

I' = new rotational inertia of drum and balls, ω' = new angular speed of drum and balls

With its new speed is now V' at the end of d,

1/2mV'² + 1/2I'ω'² = mgd

1/2mV'² = mgd - 1/2I'ω'²

V² = [2(mgd - 1/2I'ω'²)/m]

V' = √[2(mgd - 1/2I'ω'²)/m]

Since I' and ω' increase, the rotational kinetic energy of the drum and balls (1/2I'ω'²) increases. Thus, the difference (mgd - 1/2I'ω'²) < (mgd - 1/2Iω²) which implies that the kinetic energy of the box decreases. Hence, since its kinetic energy decreases, its speed V' also decreases.

So,  V' < V

So, its speed will be less than V.

3 0
3 years ago
State the law of conservation of linear momentum using Newton's third law of deduce this ​
MArishka [77]

Answer:

Derivation of Conservation of Momentum

Applying Newton's third law, these two impulsive forces are equal and opposite i.e. is equal to the change in momentum of the first object. is equal to the change in momentum of the second object. This relation suggests that momentum is conserved during the collision.

Explanation:

Hope it helps!!!

7 0
2 years ago
A car has an acceleration of -5 m/s^2. Describe the car’s motion
AlladinOne [14]

Explanation:

because the acceleration is negative, this indicates a deceleration (or slowing down) . Hence we can say that:

The car is decelerating (slowing down), i.e its velocity is decreasing, at a constant rate of 5m/s².

7 0
3 years ago
When light, starting in air, is shone on a piece of glass, what effects are you likely to observe? a. reflection b. refraction 3
PolarNik [594]

Answer:

refraction

Explanation:

When a ray of light passes from one medium to another medium, it deviates from its path, this phenomenon is called refraction.

When the ray passes from rarer medium to denser medium it bends towards the normal and if the ray passes from denser medium to rarer medium, it bends away from the normal.

Here, the ray passes from air to glass, so refraction takes place.

5 0
3 years ago
A resistor is connected to a 3.0 ???? battery. the power dissipated in the resistor is 4.0 ????. a second, identical resistor is
Svet_ta [14]

Power dissipated across any resistance is given by

P = i^2 R

now it is given that when one resistance of value 3 ohm connected the power dissipated is 4 Watt

now another identical resistance of same value is connected then the current will reduce to half of its initial value.

now power across any one resistance is given by

P = (\frac{i}{2})^2 R

So now we will have

P = \frac{i^2}{4}*R

So now the power will become 1/4 times of initial power

So now the power will be

P = 1 Watt

8 0
3 years ago
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