All categories

2 years ago

Read about reverse osmosis and multistage flash distillation .Then identify at least three advantages and three

Chemistry

1 answer:

ss7ja [257]2 years ago

7 0

Answer:

Meaning, Advantages & Disadvantages of - Osmosis, Multiflash Distillatiob

Explanation:

Osmosis is movement of solvent (like water) through semi permeable membrane (like living cell) into solution of higher solute concentration.

Advantages - It assists equalising concentration of solute on two sides of membrane. Reverse Osmosis is used for efficient water softening, it is easy to maintain.

Disadvantages - It needs a lot of energy. A lot of pressure is required for deionisation. Water acidity level increases, as minerals get deionised.

Multistage flash distillation refers to desalination water distilling seawater, by flashing water portions in steams in various stages of concurrent heat exchangers.

Advantages - Its Cost efficient , distillation uses waste heat. It has High gain output ratio. Quality of feedwater is less significant, compared to reverse osmosis.

Disadvantages - It has high operating cost in case of waste heat unavailability. High temperature imply high corrosion & scale formation.

You might be interested in

HELP!!! PLEASE!!!

elena-14-01-66 [18.8K]

Molarity is expressed as the number of moles of solute per volume of the solution. We solve the problem above as follows:

0.1000 mol Mg(NO3)2 / L (.1 L) ( 148.3 g / mol ) = 1.483 g Mg(NO3)2

0.1000 mol Sr(NO3)2 / L (.1 L) ( 211.63 g / mol ) = 2.116 g Sr(NO3)2

Hope this answers the question. Have a nice day.

8 0

3 years ago

In a mixture of 3 gases what is the total pressure of the gases if Gas A exerts a pressure

kirill [66]

Answer:

760 mm of Hg

Explanation:

If the gases A , B and C are non reacting , then according to Dalton's Law of Partial Pressure the total pressure exerted is equal to sum of individual partial pressure of the gases .

If there are n , number of gases then ,

$P_{total}= P_1+P_2+P_3+\dots +P_n$

Here ,

Partial pressure of Gas A = 400mm of Hg
Partial pressure of Gas B = 220 mm of Hg
Partial pressure of Gas C = 140mm of Hg

Hence the total pressure exerted is ,

$P_{total}= P_{Gas\ A }+P_{Gas\ B }+P_{Gas\ C }$

Substitute ,

$P_{total}=( 400 + 220 + 140 )mm\ of \ Hg$

Add ,

$P_{total}= 760\ mm\ of \ Hg$

Hence the total pressure exerted by the gases is 760 mm of Hg.

I hope this helps.

4 0

2 years ago

The hydrogen ion concentration of a vinegar solution is 0.00010 m. how is this concentration written in scientific notation?

9966 [12]

We are given with a vinegar with a hydrogen ion concentration of 0.00010 m. We are asked to express this concentration in scientific notation. The answer when expressed in scientific notation is 1x10^-4 m or molality. Answer is 1x10^-4 m.

3 0

3 years ago

Read 2 more answers

A 0.1873 g sample of a pure, solid acid, H2X (a diprotic acid) was dissolved in water and titrated with 0.1052 M NaOH solution.

puteri [66]

Answer:

We need 41.8 mL of NaOH

Explanation:

Step 1: Data given

Mass of H2X = 0.1873 grams

Molarity of NaOH solution = 0.1052 M

Molar mass of H2X = 85.00 g/mol

Step 2: The balanced equation

H2X (aq) +2 NaOH (aq) → Na2X (aq) + 2H2O(l)

Step 3: Calculate moles of H2X

Moles H2X = mass H2X / Molar mass H2X

Moles H2X = 0.1873 grams / 85.00 g/mol

Moles H2X = 0.0022 moles

Step 4: Calculate moles of NaOH

For 1 mol H2X we need 2 moles NaOH to produce 1 mole of Na2X and 2 moles of H2O

For 0.0022 moles of H2X we need 0.0044 moles of NaOH

Step 5: Calculate volume of NaOH

Volume of NaOH = moles of NaOH / molarity of NaOH

Volume of NaOH = 0.0044 moles / 0.1052 M

Volume NaOH = 0.0418 L = 41.8 mL

We need 41.8 mL of NaOH

6 0

3 years ago

A chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution? A

anygoal [31]

this is a dilution equation where 50.0 mL of 1.50 M H₂SO₄ is taken and added to 200 mL of water.

c1v1 = c2v2

where c1 is concentration and v1 is volume of the concentrated solution

and c2 is concentration and v2 is volume of the diluted solution to be prepared

50.0 mL of 1.50 M H₂SO₄ is added to 200 mL of water so the final solution volume is - 200 + 50.0 = 250 mL

substituting these values in the formula

1.50 M x 50.0 mL = C x 250 mL

C = 0.300 M

concentration of the final solution is A) 0.300 M

4 0

3 years ago

Read 2 more answers