Answer:
Value of magnitude of acceleration will be 
Explanation:
It is given that when a stone is dropped it takes 2.2 sec to reach the ground
(a) As the stone is dropped from the top of building
So its initial velocity
will be 0 m /sec
(b) As the stone is free falling and there is no external force applied on it so its acceleration will be equal to acceleration due to gravity
So value of magnitude of acceleration will be equal to
Charge of electron = 1.6×10−¹⁹
(1.6×10−¹⁹)(1×10²) (2e)
= 3.2×10−¹⁷ J
10.92N
Explanation:
Given parameters:
Mass of truck = 2.964kg
Velocity of truck = 7m/s
Time taken = 1.9s
Unknown:
Average force on the car = ?
Solution:
According to newton's third law of motion "action and reaction are equal and opposite".
The force with which the truck struck the fence is the same as the force the fence acted on the truck with but in another direction.
From newton's second law:
Force = mass x acceleration
We know that acceleration is the change in velocity with time;
acceleration =
Force = mass x
Force =
= 10.92N
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Newton's laws brainly.com/question/11411375
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Answer:
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Explanation:
when a hole is made at the bottom of the container then water will flow out of it
The speed of ejected water can be calculated by help of Bernuolli's equation and Equation of continuity.
By Bernoulli's equation we can write

Now by equation of continuity


from above equation we can say that speed at the top layer is almost negligible.

now again by equation of continuity


here we have


now speed is given by

