A.
because the nucleus contains protons and neutrons BUT neutrons are neutral and protons are positive, so the answer is A
It would be: Activation Energy = 300 KJ
Hope this helps!
Answer:
reduction in the amount of CO₂ emissions by that household per year is 9517.2 lbm per year
Explanation:
given data
electricity consume = 14000 kWh
fuel consume = 900 gal
CO₂ produced of fuel = 26.4 lbm/gal
CO₂ produced of electricity = 1.54 lbm/kWh
oil and electricity usage = 21 percent
to find out
the reduction in the amount of CO₂ emissions
solution
we calculate the amount of CO₂ produce here that is
amount of CO₂ produce = ( electricity consume×CO₂ produce electricity + fuel consume × CO₂ consume fuel ) ........................1
put here value
amount of CO₂ produce = ( 14000 × 1.54 + 900 × 26.4 )
amount of CO₂ produce = 45320 lbm/yr
we know reduction is 21%
so
reduction in amount of CO₂ produced is
reduction in CO₂ produced = 45320 × 21%
reduction in CO₂ produced = 9517.2 lbm per year
so reduction in the amount of CO₂ emissions by that household per year is 9517.2 lbm per year
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sorry this is by accident, but i can't delete it
K.E = 1/2mv^2
The kinetic energy is 50,000 J and the mass of the car is 10,000 kg.
50,000 J = 1/2(10,000kg)v^2
Solve for v (velocity)
50,000 J = 5,000 kg x v^2
10 = v^2
about 3 m/s (in terms of significant figures)
