All categories

3 years ago

A 1000-kg car has 50,000 joules of kinetic energy. What is the speed?

Physics

2 answers:

bixtya [17]3 years ago

5 0

Answer:

½mv²= KE

½(1000)?²= 50000

500 500

? ²=100

Square root

?= 10

10 m/s is you answer

djyliett [7]3 years ago

4 0

K.E = 1/2mv^2

The kinetic energy is 50,000 J and the mass of the car is 10,000 kg.

50,000 J = 1/2(10,000kg)v^2
Solve for v (velocity)
50,000 J = 5,000 kg x v^2
10 = v^2
$\sqrt{10} = v$
about 3 m/s (in terms of significant figures)

You might be interested in

The volume of an object as a function of time is V(t) = At³, where A is a constant. Let L and T denote dimensions of length and

Greeley [361]

Answer:

c) L³/T³

Explanation:

If t stands for time, the units are:

(V) = L³, (t) = T

The units for the equation:

V(t) = At³

must be:

$L^{3} = \frac{L^{3} }{T^{3}} T^{3}$

7 0

3 years ago

Which of these is the movement of material cause by the interaction between worm and cool material?

mr Goodwill [35]

Convection Current
This happens when there is a noteworthy contrast in temperature between two sections of a liquid. At the point when this temperature distinction exists, hot liquids rise and cool liquids sink, and after that streams, or developments, are made in the liquid

7 0

3 years ago

When the speed of your car is doubled, by what factor does its kinetic energy increase?

Tju [1.3M]

Answer:

a. 4

Explanation:

Hi there!

The equation of kinetic energy (KE) is the following:

KE = 1/2 · m · v²

Where:

m = mass of the car.

v = speed of the car.

Let´s see how would be the equation if the velocity is doubled (2 · v)

KE2 = 1/2 · m · (2 · v)²

Distributing the exponent:

KE2 = 1/2 · m · 2² · v²

KE2 = 1/2 · m · 4 · v²

KE2 = 4 (1/2 · m · v²)

KE2 = 4KE

Doubling the velocity increased the kinetic energy by 4.

7 0

3 years ago

A circus tightrope walker weighing 800 N is standing in the middle of a 15 meter long cable stretched between two posts. The cab

Lorico [155]

Answer:

T = 10010 N

Explanation:

To solve this problem we must use the translational equilibrium relation, let's set a reference frame

X axis

Fₓ-Fₓ = 0

Fₓ = Fₓ

whereby the horizontal components of the tension in the cable cancel

Y Axis

$F_{y} + F_{y} - W =0$

2 $F_{y}$ = W

let's use trigonometry to find the angles

tan θ = y / x

θ = tan⁻¹ (0.30 / 0.50 L)

θ = tan⁻¹ (0.30 / 0.50 15)

θ = 2.29º

the components of stress are

F_{y} = T sin θ

we substitute

2 T sin θ = W

T = W / 2sin θ

T = $\frac{ 800}{ 2sin 2.29}$

T = 10010 N

4 0

3 years ago

A car with a mass of 1,500 kg is traveling at a speed of 30 m/s. What force must be applied to stop the car in 3 seconds?

QveST [7]

Explanation:

F = ma

F = m Δv / Δt

F = (1500 kg) (0 m/s − 30 m/s) / 3 s

F = -15,000 N

3 0

3 years ago