X-1=-2x+5
X=2
Y=-2(2) + 5
Y= 1
Distribute first so
2x-x+2=2-x+1
Combine like terms so
x+2=3-x
Get terms on the same side so
2x+2=3
Subtract 2
2x=1
Divide
X=1/2 or .5
<span>∫(sinx cosx)^2dx = ∫(1/2sin 2x)^2 dx = 1/4∫sin^2 2x dx = 1/4∫1/2(1 - cos 4x)dx = 1/8∫(1 - cos 4x) dx = 1/8[x - sin 4x / 4] + c = 1/32(4x - sin 4x) + c
</span>
28(8) = 224
224(5) = 1,120
1,120(50) = 56,000
Answer: 56,000
Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)