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Luba_88 [7]
3 years ago
13

~good mornin~ hru guys want too talk

Chemistry
1 answer:
asambeis [7]3 years ago
4 0

Answer:

Ok let's do this how are you❤️

You might be interested in
Do chemical equations with no reaction still have to be balanced
dangina [55]

Answer:

The same number of atoms of each element must appear on both sides of a chemical equation. However, simply writing down the chemical formulas of reactants and products does not always result in equal numbers of atoms. You have to balance the equation to make the number of atoms equal on each side of an equation.

Explanation:

5 0
3 years ago
How many atoms of oxygen are present in the reactants and products? 6CO2+6H2O-> C6H12O6+6O2
REY [17]
6 Carbon atoms
18 Oxygen atoms
12 Hydrogen atoms
6 0
3 years ago
Identify the oxidized and reduced forms from the following pairs:
Luden [163]

Answer:

1. NAD⁺ is the oxidized form and NADH  is the reduced form

2. Pyruvate is the oxidized form and Lactate is the reduced form.

3. Oxaloacetate is the oxidized form and Malate is the reduced form.

4. Fumarate is the oxidized form and Succinate is the reduced form.

5. FMN is the oxidized form and FMNH₂  is the reduced form

6. α-ketoglutarate is the oxidized form and Isocitrate is the reduced form.

7. O₂ is the oxidized form and  H₂O₂ is the reduced form.

Explanation:

Oxidation is the gain of oxygen or loss of electrons or hydrogen. Whereas, reduction is the loss of oxygen or gain of electrons or hydrogen.

1. NAD⁺/NADH

<u>NAD⁺ is the oxidized form and NADH  is the reduced form of Nicotinamide adenine dinucleotide, NAD.</u>

Therefore, NAD⁺ gets reduced to NADH by accepting electrons and proton.

NAD⁺ + 2 e⁻ + H⁺ → NADH

2. Pyruvate/lactate

Pyruvate, CH₃COCOO⁻, is the conjugate base of Pyruvic acid.

Lactate, CH ₃CH(OH)COO⁻, is the conjugate base of Lactic acid.

Reduction of Pyruvate to lactate:

CH₃COCOO⁻ + NADH  ⇌ CH ₃CH(OH)COO⁻ + NAD⁺

This reaction is catalyzed by the enzyme lactate dehydrogenase.

<u>Therefore, Pyruvate is the oxidized form and Lactate is the reduced form.</u>

3. Malate/oxaloacetate

Oxaloacetate, ⁻O₂CC(O)CH₂CO₂⁻, is the conjugate base of oxaloacetic acid.

Malate,⁻O₂CCH(OH)CH₂CO₂⁻, is the conjugate base of Malic acid.

Oxidation of Malate to Oxaloacetate:

⁻O₂CCH(OH)CH₂CO₂⁻ + NAD⁺  ⇌ ⁻O₂CC(O)CH₂CO₂⁻ + NADH

This reaction is catalyzed by the enzyme malate dehydrogenase.

<u>Therefore, Oxaloacetate is the oxidized form and Malate is the reduced form.</u>

4. Fumarate/succinate

Fumarate, ⁻O₂CCH=CHCO₂⁻, is the conjugate base of Fumaric acid.

Succinate, ⁻O₂CCH₂CH₂CO₂⁻, is the conjugate base of Succinic acid.

Oxidation of succinate to fumarate:

⁻O₂CCH₂CH₂CO₂⁻ + FAD ⇌ ⁻O₂CCH=CHCO₂⁻ + FADH₂

This reaction is catalyzed by the enzyme succinate dehydrogenase.

<u>Therefore, fumarate is the oxidized form and succinate is the reduced form.</u>

<u />

5. FMN/FMNH₂

<u>FMN is the oxidized form and FMNH₂  is the reduced form</u> of riboflavin-5′-phosphate or Flavin mononucleotide.

Therefore, FMN gets reduced to FMNH₂  by accepting electrons and proton.

FMN + 2 e⁻ + 2H⁺ → FMNH₂

     

6. α-ketoglutarate/isocitrate

α-ketoglutarate, ⁻O₂CC(O)CH₂CH₂CO₂⁻, is the conjugate base of α-Ketoglutaric acid.

Isocitrate, ⁻O₂CCH(OH)CH(CO₂⁻)CH₂CO₂⁻, is the conjugate base Isocitric acid.

Oxidation of Isocitrate to α-ketoglutarate:

⁻O₂CCH(OH)CH(CO₂⁻)CH₂CO₂⁻ + NAD⁺ → ⁻O₂CC(O)CH₂CH₂CO₂⁻ + CO₂ + NADH

This reaction is catalyzed by the enzyme Isocitrate dehydrogenase.

<u>Therefore, α-ketoglutarate is the oxidized form and Isocitrate is the reduced form.</u>

<u />

7. H₂O₂/O₂

Hydrogen peroxide, H₂O₂, is synthesized from hydrogen (H₂) and oxygen (O₂) in the presence of a catalyst.

H₂ + O₂ → H₂O₂

Oxygen gets reduced from 0 oxidation state in O₂ to -1 oxidation state in H₂O₂.

<u>Therefore, O₂ is the oxidized form and  H₂O₂ is the reduced form.</u>

8 0
3 years ago
Which of the following are observations? Select all that apply.
iris [78.8K]

Answer:

All are correct

Explanation:

3 0
3 years ago
For a snack, I ate 40 gummy bears. Each gummy bear weighs 3g.
slega [8]

Taking into account the rule of three, you eat 480 kcal.

<h3>Rule of three</h3>

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.  

If the relationship between the magnitudes is direct, the direct rule of three must be applied as follow, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: x= (c×b)÷ a

<h3>kcal of eaten gummy bears</h3>

To know the mass of eaten gummy bears, the following rule of three applies: if 1 gummy bear weighs 3 g, 40 gummy bears weigh how much mass?

1 gummy bear ⇒ 3 g

40 gummy bears ⇒ x

So: x= (40 gummy bears× 3 g)÷ 1 gummy bear

Solving:

<u><em>x= 120 g</em></u>

If gummy bears are 100% carbohydrates and carbohydrates are 4 kcal/g, the following rule of three applies: If 1 g has 4 kcal, 120 g has how many kcal?

1 g ⇒ 4 kcal

120 g⇒ x

So: x= (120 g× 4 kcal)÷ 1 g

Solving:

<u><em>x= 480 kcal</em></u>

In summary, you eat 480 kcal.

Learn more with this example:

brainly.com/question/12482948

#SPJ1

4 0
1 year ago
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